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TiliK225 [7]
3 years ago
11

The Environmental Protection Agency has ben concerned about the levels of radon gas in homes. If a sample of gas taken from a ba

sement contains 4.38 g of radon 222, how much radon will remain in the sample after 4 half-lives?
0.28 g

2.19 g

1.10 g

4.38 g
Physics
1 answer:
soldier1979 [14.2K]3 years ago
6 0
Answer is 2.19 g of radon will remain in the sample after 4 half-lives
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What is the speed of a transverse wave in a rope of length 3.1 m and mass 86 g under a tension of 380 n?
stellarik [79]

The speed of a transverse wave( v) = 117.03 m/s

The formula we can use in this case would be:

v = sqrt (T / (m / l))

Where,

v = is the velocity of the transverse wave = unknown (?)

T = is the tension on the rope = 380 N

m = is the mass of the rope = 86.0 g = 0.086 kg

l = is the length of the rope = 3.1 m

Substituting the given values into the equation to search for the speed v:

v = sqrt (380 N/(0.086 kg /3.1 m))

v = sqrt (380 * 3.1/ 0.086)

v = sqrt (13,697.67)

v = 117.03 m/s

speed of a transverse wave( v) = 117.03 m/s

Learn more about  transverse wave here:

brainly.com/question/23165088

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4 0
1 year ago
A ray is incident on a film of thickness t and the index of refraction n=1.6 at an angle θ = 35 degrees. Find the angle of refra
lidiya [134]

Answer

Given,

refractive index of film, n = 1.6

refractive index of air, n' = 1

angle of incidence, i = 35°

angle of refraction, r = ?

Using Snell's law

n' sin i = n sin r

1 x sin 35° = 1.6 x sin  r

 r = 21°

Angle of refraction is equal to 21°.

Now,

distance at which refractive angle comes out

d = 2.5 mm

α be the angle with horizontal surface and incident ray.

α = 90°-21° = 69°

t be the thickness of the film.

So,

tan \alpha = \dfrac{t}{d/2}

tan 61^0 = \dfrac{t}{2.5/2}

t = 2.26 mm

Hence, the thickness of the film is equal to 2.26 mm.

4 0
3 years ago
A ray of light passes from air into carbon disulfide (n = 1.63) at an angle of 28.0 degrees to the normal. what is the refracted
Snezhnost [94]
We can solve the problem by using Snell's law, which states 
n_i \sin \theta_i = n_r \sin \theta_r
where
n_i is the refractive index of the first medium
\theta_i is the angle of incidence
n_r is the refractive index of the second medium
\theta_r is the angle of refraction

In our problem, n_i=1.00 (refractive index of air), \theta_i = 28.0^{\circ} and n_r=1.63 (refractive index of carbon disulfide), therefore we can re-arrange the previous equation to calculate the angle of refraction:
\sin \theta_r =  \frac{n_i}{n_r}  \sin \theta_r =  \frac{1.00}{1.63}  \sin 28.0^{\circ} = 0.288
From which we find
\theta_r = \arcsin (0.288)=16.7^{\circ}
6 0
3 years ago
A 10 g bullet accelerates to 400 m/s after being fired from a gun with a mass of 2.0 kg.
Gala2k [10]

Answer:

See the answers below.

Explanation:

Momentum is defined as the product of mass by velocity, and can be calculated by means of the following expression.

P=m*v

where:

P = Momentum [kg*m/s]

m = mass = 10 [g] = 0.01 [kg]

v = velocity = 400 [m/s]

i)

P=0.01*400\\P=4[kg*m/s]

ii)

The momentum of the gun is equal to zero, because it does not move before being fired, the weapon only moves after having fired the weapon.

P_{gun}=0

iii)

Since the momentum is conserved before and after the shot, the same momentum given to the bullet is equal to the momentum received by the gun.

P=m*v_{recoil}

v_{recoil}=P/m\\v_{recoil}= 4/2\\v_{recoil}=2[m/s]

3 0
3 years ago
Weight and mass are interchangeable terms. True or False
Nonamiya [84]
It's false. Mass is a way of measuring how much matter an object contains, where as weight measures how hard gravity is pulling on an object. While on earth, these are typically interchangeable. However, if you were to go to Mars, your mass would stay the same, but the weight will be different. This is because you still contain the same amount of matter, but the gravity's pull will be different because the moon has a different gravitational pull than the earth. Hope this helps!
5 0
3 years ago
Read 2 more answers
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