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3 years ago

Can someone please help me with this expression?

Mathematics

1 answer:

Anton [14]3 years ago

7 0

the answer to this question is

1220703125

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Rachel bought 2 pounds of apples and 3 pounds of peaches for a total of $20.45. The apples and peaches cost the same amount per

Likurg_2 [28]

Each pound would cost at least 4.09$

8 0

3 years ago

Complete the given ordered pairs for the equation. y = 2x + 1 (5, ) (0, ) (-2, )

VikaD [51]

Answer:

(5,11)

(0,1)

(-2,-3)

Step-by-step explanation:

y=2(5)+1

y=10+1

y=11

so... (5,11)

y=2(0)+1

y=0+1

y=1

so... (0,1)

y=2(-2)+1

y=-4+1

y=-3

so... (-2,-3)

6 0

3 years ago

Given f(x)=22x+12, find f(7)

Zarrin [17]

Substitute x for 7.

f(x)=22x+12

f(7)=22(7)+12

Multiply first, then complete addition.

f(7)=154+12

f(7)=166

4 0

3 years ago

Read 2 more answers

Which shape is similar to the original shape? A) A B) B C) C D) D

Anna35 [415]

Answer:

I think the answer is A.

Step-by-step explanation:

Original shape: 7 x 5 x 225 x 6 x 12 x 45 = 25,515,000

A: 9 x 5 x 225 x 6 x 35 x 12 = 25,515,000

B: 14 x 10 x 255 x 12 x 24 x 45 = 462,672,000

C: 9 x 7 x 225 x 8 x 15 x 45 = 76,545,000

D: 8 x 4 x 225 x 6 x 12 x 35 = 18,144,000

This is probably not the way you would solve it but this is how I did it. Basically I multiplied all the numbers in each shape together.

(also i'm not quite sure if this is right >.< sorry!)

8 0

3 years ago

Heights of young adult women in the United States are approximately Normal with a mean of 64 inches and standard deviation 2.7 i

sweet-ann [11.9K]

Answer:

The proportion of all young adult women in the United States are taller than 6 feet(72 inches ) is

$P( X > 72) =0.0015233$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 64 \ inches$

The standard deviation is $\sigma = 2.7 \ inches$

Generally 6 feet is equivalent to 6 * 12 = 72 inches

Generally the proportion of all young adult women in the United States are taller than 6 feet(72 inches ) is mathematically represented as

$P( X > 72) = P(\frac{X - \mu }{\sigma } > \frac{72 - 64 }{ 2.7 } )$

$\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )$

$P( X > 72) = P(Z > 2.963 )$

From the z-table

The area under the normal curve to the right corresponding to 2.963 is

$P(Z > 2.963 ) = 0.0015233$

=> $P( X > 72) =0.0015233$

3 0

3 years ago