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Nadusha1986 [10]
3 years ago
8

Which element has a crystalline lattice through which electrons flow freely

Chemistry
1 answer:
xxTIMURxx [149]3 years ago
5 0

Answer:

Copper

Explanation:

Metals are often arranged in crystalline lattices. The lattice consists of metal ions with an overlying sea of electrons. The conductivity of a metal depends on the nature of this crystal lattice. Naturally, some metals conduct electricity better than others. The unique properties of the crystal lattice of copper allow electrons to flow through it freely especially when it is drawn into a wire.

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During which stage of the cell cycle dies the cell condense chromosomes and break down the nuclear envelope
saveliy_v [14]

Answer:

Prophase

Explanation:

During prophase, the chromosomes condense, the nucleolus disappears, and the nuclear envelope breaks down.

5 0
3 years ago
Please help i dont have much time cause i have to give it in soon :,)
Hitman42 [59]

Answer:

HBr + KOH = KBr + H2O

3 HF + Fe(OH)3 = FeF3 + 3 H2O

2 HCl + Ca(OH)2 = CaCl2 + 2 H2O

Explanation:

7 0
2 years ago
Can someone please please help
Llana [10]

Answer:

oxidizer

Explanation:

an example of an oxidizers are oxygen and hydrogen peroxide

7 0
3 years ago
Melamine, C3N3(NH2)3, is used in adhesives and resins. It is manufactured in a two-step process: CO(NH2)2(l) → HNCO(l) + NH3(g)
svetlana [45]

Answer:

43.13Kg of melamine

Explanation:

The problem gives you the mass of urea and two balanced equations:CO(NH_{2})_{2}_{(l)}=HNCO_{(l)}+NH_{3}_{(g)}

6HNO_{l}=C_{3}N_{3}(NH_{2})_{3}_{(l)}+3CO_{2}_{(g)}

First we need to calculate the number of moles of urea that are used in the reaction, so:

molar mass of urea = 60.06\frac{g}{mol}*\frac{1kg}{1000g}=0.06006\frac{Kg}{mol}

The problem says that you have 161.2Kg of urea, so you take that mass of urea and find the moles of urea:

161.2Kg of urea*\frac{1molofurea}{0.06006Kgofurea}=2684 moles of urea

Now from the stoichiometry you have:

2684 moles of urea*\frac{1molofHNCO}{1molurea}*\frac{1molofmelamine}{6molesofHNCO} = 447 moles of melamine

The molar mass of the melamine is 126.12\frac{g}{mol} so we have:

447molesofmelamine*\frac{126.12g}{1molofmelamine} = 5637.64 g of melamine

Converting that mass of melamine to Kg:

5637.64 g of melamine *\frac{1Kg}{1000g} = 56.38 Kg of melamine, that is the theoretical yield of melamine.

Finally we need to calculate the mass of melamine with a yield of 76.5%, so we have:

%yield = 100*(Actual yield of melamine / Theoretical yield of melamine)

Actual yield of melamine = \frac{76.5}{100}*56.38Kg = 43.13Kg of melamine

8 0
3 years ago
Write a formula for the ionic compound that forms from magnesium<br> and oxygen.
Fed [463]

Answer:

MgO

Explanation:

8 0
3 years ago
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