All categories

1 year ago

An ion has 56 protons, 54 electrons, and 81 neutrons. What is its atomic number ?

Chemistry

2 answers:

-BARSIC- [3]1 year ago

8 0

The Atomic Number indicates the number of protons = 56

EastWind [94]1 year ago

5 0

Answer: The barium – 137 atom would have 56 protons, 56 electrons and 81 neutrons. The barium – 137 cation would have 56 protons, 54 electrons and 81 neutrons.

Explanation: Hope this is helpful

You might be interested in

Ask BRIA

Blizzard [7]

Answer:

o temperature increases

5 0

3 years ago

select which of the following correctly represents the BALANCED chemical reaction for the production of HCL gas from its element

bagirrra123 [75]

Answer:

Choices 2 and 4

Explanation:

HCL is formed witthe the elements Hydrogen and Chlorine. Whatever is on the left side of the equation must match up with the right side of the equation.

2. H + Cl --> HCl (we have one hydrogen and one chlorine)

4. 2HCl --> H2 + Cl2 (since the two is distributed to both the H and the Cl, H has 2 and Cl has two on the left side AND on the right side of the equation)

3 0

2 years ago

1. If 80.0 ml of 3.00 M HCl is used to make a 100. ml of dilute acid, what is the molarity

Aleonysh [2.5K]

We are given:

M1 = 3 Molar V1 = 80 mL

M2 = x Molar V2 = 100 mL

Finding the molarity:

We know that:

M₁V₁ = M₂V₂

where V can be in any units

(3)(80) = (x)(100)

x = 240/100 [dividing both sides by 100]

x = 2.4 Molar

3 0

2 years ago

with the help of balanced chemical equation explain what happens when zinc is put in dilute hydrochloric acid

blagie [28]

They react to form salt ZnCl + hydrogen gas

3 0

2 years ago

At standard temperature and pressure. 0.500 mole of xenon gas occupies

ANEK [815]

Answer:

0.500 mole of Xe (g) occupies 11.2 L at STP.

General Formulas and Concepts:

Gas Laws

STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Stoichiometry

Mole ratio
Dimensional Analysis

Explanation:

Step 1: Define

Identify.

0.500 mole Xe (g)

Step 2: Convert

[DA] Set up: $\displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg)$
[DA] Evaluate: $\displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg) = 11.2 \ \text{L Xe}$

Topic: AP Chemistry

Unit: Stoichiometry

3 0

1 year ago