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Andrej [43]
3 years ago
5

How much work would it take to push two protons very slowly from a separation of 2.00×10−10m (a typical atomic distance) to 3.00

×10−15m (a typical nuclear distance)?
Chemistry
1 answer:
mixer [17]3 years ago
5 0

Answer: 7.68×10^14 J

Explanation:

The magnitude of the charge q1=q2 = 1.6×10^-19 C

Proportionality constant K = 9×10^9 Nm²/C²

Da= 2×10^-10m

Db= 3 ×10^-15m

W= k q1q2 ( 1/Db -1/Da)

W= 9×10^9 (1.69×10^-19)²(1/3.0×10^-15 - 1/2×10^-10)

W= 7.68 ×10^-14J

Therefore the amount of work requires is 7.68 ×10^-14J

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Hello there!

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