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aniked [119]
3 years ago
13

Joe has 1/2 of a pound of peanuts. He wants to share them equally among himself and 3 friends.

Mathematics
2 answers:
stealth61 [152]3 years ago
6 0

Answer:

Each would get 0.125 pounds

Step-by-step explanation:

Divide 1/2 by 4 and you get 0.125

stira [4]3 years ago
5 0

Answer: Each person will get 1/6 pounds of peanuts.

Step-by-step explanation:

Hi, to answer this question we simply have to divide the amount of peanuts that Joe has (1/2 pounds) and divide it by the number of friends (3).

Mathematically speaking:

1/2 pounds of peanuts / 3 friends = 1/2 ÷ 3 = 1/6 pounds of peanuts per friend.

So, each person will get 1/6 pounds of peanuts.

Feel free to ask for more if needed or if you did not understand something.

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John and Kamira are playing a game. John scores - 5 in the first round, while Kamira scores 7.
disa [49]

Answer:

the sum of John's score and Kamira's score

Step-by-step explanation:

-5 + 7 = 2

8 0
3 years ago
You deposit $2000 each year into an account earning 3% interest compounded annually. How much will you have in the account in 25
kozerog [31]

This is what I get.  Total will be 4187.56 with  Interest 2187.56.   By using the formula: To find amount : A=p (1+r/n)^n×t Where P=2000,r=3%,n=1,t=25 So plug in and solve  A=2000(1+0.03/1)^1×25   To find interest you use formula  A=p+I A=4187.56, p=2000,i= we need to find. 4187.56=2000+I 4187.56-2000=I 2187.56=i

3 0
3 years ago
WILL GIVE BRAINLIST IF ANSWERS QUICKLY!
stealth61 [152]

Answer:

choice a is the answer

0.17

Step-by-step explanation:

5 0
3 years ago
-How to simplify y^3Z^5/Y^2Z^3?
Romashka [77]

Answer:

=yz8

Step-by-step explanation:

I HOPE THIS HELPS ^^!!

8 0
3 years ago
Suppose 12% of students are veterans. From a sample of 263 students, how unusual would it be to have less than 22 veterans?
kkurt [141]

Answer:

Yes, both np and n(1-p) are ≥ 10

Mean = 0.12 ; Standard deviation = 0.02004

Yes. There is a less than 5% chance of this happening by random variation. 0.034839

Step-by-step explanation:

Given that :

p = 12% = 0.12 ;

Sample size, n = 263

np = 263 * 0.12 = 31.56

n(1 - p) = 263(1 - 0.12) = 263 * 0.88 = 231.44

According to the central limit theorem, distribution of sample proportion approximately follow normal distribution with mean of p = 0.12 and standard deviation sqrt(p*(1 - p)/n) = sqrt (0.12 *0.88)/n = sqrt(0.0004015) = 0.02004

Z = (x - mean) / standard deviation

x = 22 / 263 = 0.08365

Z = (0.08365 - 0.12) / 0.02004

Z = −1.813872

Z = - 1.814

P(Z < −1.814) = 0.034839 (Z probability calculator)

Yes, it is unusual

0.034 < 0.05 (Hence, There is a less than 5% chance of this happening by random variation.

7 0
3 years ago
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