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mestny [16]
4 years ago
11

Identify two potential improvements to the opal extraction process and explain how these improvements could minimize harm to the

environment.
Physics
1 answer:
Orlov [11]4 years ago
7 0

Answer

• Improving the environmental performances

• Developing Green Mining technology

Explanation

The effect to the environment caused by opal mining are; impact on soils and geology, clearing of native vegetation disrupting flora and fauna, change in land use and effects of air quality.

Opal mining is currently examining environmental impacts and adopting measures that mitigate the impacts making the process less destructive to the environment.

With the current commitment to sustainability, opal companies are investing funds for Green Mining as a positive way to impact the environment before and after mining.


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One with greater mass (8kg)
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What is the force of lift and its applications​
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Answer:

fluid flowing past the surface of a body exerts a force on it. Lift is the component of this force that is perpendicular to the oncoming flow direction.[1] It contrasts with the drag force, which is the component of the force parallel to the flow direction. Lift conventionally acts in an upward direction in order to counter the force of gravity, but it can act in any direction at right angles to the flow.

If the surrounding fluid is air, the force is called an aerodynamic force. In water or any other liquid, it is called a hydrodynamic force.

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50g of ice at 0°C is mixed with 50g of water at 80°C, what will be the final temperature of a mixture in
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Answer:

0° C

Explanation:

Given that

Mass of ice, m = 50g

Mass of water, m(w) = 50g

Temperature of ice, T(i) = 0° C

Temperature of water, T(w) = 80° C

Also, it is known that

Specific heat of water, c = 1 cal/g/°C

Latent heat of ice, L(w) = 89 cal/g

Let us assume T to be the final temperature of mixture.

This makes the energy balance equation:

Heat gained by ice to change itself into water + heat gained by melted ice(water) to raise its temperature at T° C = heat lost by water to reach at T° C

m(i).L(i) + m(i).c(w)[T - 0] = m(w).c(w)[80 - T], on substituting, we have

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With time running out in a game, Rachel runs towards the basket at a speed of 2.5 meters per second and from half-court, launche
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b.R=10.15m/s, 27.57deg

Explanation:

The reference angle of Rachel is 00^{0} while the ball is at 36^{0}

resolving rachel's speed to the horizontal, we have

Ux=2.5cos0

Ux=2.5m/s

resolving rachel's speed to the vertical we have,

Uy=2.5sin0

Uy=0

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resolving the speed to its horizontal component

Ux=8cos36

Ux=6.5m/s

Uy=8sin36

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To get the resultant of their speed

Add the horizontal speed of rachel to that of the ball to get the total horizontal speed

Add the vertical speed of rachel and the ball to get the total vertical speed component

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R=\sqrt{(103)}

R=10.15m/s

the direction

tan\alpha=TUy/TUx

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