One with greater mass (8kg)
Answer:
fluid flowing past the surface of a body exerts a force on it. Lift is the component of this force that is perpendicular to the oncoming flow direction.[1] It contrasts with the drag force, which is the component of the force parallel to the flow direction. Lift conventionally acts in an upward direction in order to counter the force of gravity, but it can act in any direction at right angles to the flow.
If the surrounding fluid is air, the force is called an aerodynamic force. In water or any other liquid, it is called a hydrodynamic force.
Dynamic lift is distinguished from other kinds of lift in fluids. Aerostatic lift or buoyancy, in which an internal fluid is lighter than the surrounding fluid, does not require movement and is used by balloons, blimps, dirigibles, boats, and submarines. Planing lift, in which only the lower portion of the body is immersed in a liquid flow, is used by motorboats, surfboards, and water-skis.
Answer:
0° C
Explanation:
Given that
Mass of ice, m = 50g
Mass of water, m(w) = 50g
Temperature of ice, T(i) = 0° C
Temperature of water, T(w) = 80° C
Also, it is known that
Specific heat of water, c = 1 cal/g/°C
Latent heat of ice, L(w) = 89 cal/g
Let us assume T to be the final temperature of mixture.
This makes the energy balance equation:
Heat gained by ice to change itself into water + heat gained by melted ice(water) to raise its temperature at T° C = heat lost by water to reach at T° C
m(i).L(i) + m(i).c(w)[T - 0] = m(w).c(w)[80 - T], on substituting, we have
50 * 80 + 50 * 1(T - 0) = 50 * 1(80 - T)
4000 + 50T = 4000 - 50T
0 = 100 T
T = 0° C
Thus, the final temperature is 0° C
Answer:
Rachel(2.5,0)
ball(6.5,4.7)
b.R=10.15m/s, 27.57deg
Explanation:
The reference angle of Rachel is 0
resolving rachel's speed to the horizontal, we have
Ux=2.5cos0
Ux=2.5m/s
resolving rachel's speed to the vertical we have,
Uy=2.5sin0
Uy=0
for the ball
resolving the speed to its horizontal component
Ux=8cos36
Ux=6.5m/s
Uy=8sin36
Uy=4.7m/s
Rachel(2.5,0)
ball(6.5,4.7)
To get the resultant of their speed
Add the horizontal speed of rachel to that of the ball to get the total horizontal speed
Add the vertical speed of rachel and the ball to get the total vertical speed component
TUx=2.5+6.5=9M/S
TUy=0+4.7=4.7m/s
R=
R=
R=
R=10.15m/s
the direction
tan
=TUy/TUx
tan
=4.7/9
=tan^-1(0.522)
=27.57deg
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