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3 years ago

PLEASE HELP! If the period of a mass spring oscillator is 8π s and the spring constant is 2 N/m, how much mass is attached?

Physics

1 answer:

xxTIMURxx [149]3 years ago

4 0

The period of a mass-spring system is:

T = 2π $\sqrt{m/k}$

T = period, m = mass, k = spring constant

Given values:

T = 8π s

k = 2 N/m

Plug in and solve for m:

8π = 2π $\sqrt{m/2}$

$\sqrt{m/2}$ = 4

m/2 = 16

m = 32 kg

Choice A

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0.63

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4 years ago

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3 years ago

Vector A, with magnitude 28.0 units, points in the positive y-direction. Vector A + B has a magnitude of 19.0 units and points i

Leokris [45]

<h2>Answer:</h2>

|B| = 47.0 units

<h2>Explanation:</h2>

The sum of two vectors (A) and (B) gives another vector (A + B). i.e

(A + B) = (A) + (B) ----------------(i)

<em>From the question;</em>

Vector A = 28.0 units in the positive y-direction. This means that the value of the x-component is zero and the value of the y-component is +28

In unit vector notation vector A is given as;

A = 0i + 28.0j

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In unit vector notation, vector A + B is given as;

A + B = 0i - 19.0j

To get the magnitude of vector B, make B the subject of the formula in equation (i) as follows;

(B) = (A + B) - (A) ------------------ (ii)

Substitute the values of the vectors (A) and (A + B) into equation (ii) as follows;

(B) = (0i - 19.0j) - (0i + 28.0j)

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4 years ago