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LUCKY_DIMON [66]
3 years ago
14

PLEASE HELP! If the period of a mass spring oscillator is 8π s and the spring constant is 2 N/m, how much mass is attached?

Physics
1 answer:
xxTIMURxx [149]3 years ago
4 0

The period of a mass-spring system is:

T = 2π\sqrt{m/k}

T = period, m = mass, k = spring constant

Given values:

T = 8π s

k = 2 N/m

Plug in and solve for m:

8π = 2π\sqrt{m/2}

\sqrt{m/2} = 4

m/2 = 16

m = 32 kg

Choice A

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