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Paladinen [302]
4 years ago
9

Vector A, with magnitude 28.0 units, points in the positive y-direction. Vector A + B has a magnitude of 19.0 units and points i

n the −y-direction. What is the magnitude of B?
Physics
1 answer:
Leokris [45]4 years ago
8 0
<h2>Answer:</h2>

|B|  = 47.0 units

<h2>Explanation:</h2>

The sum of two vectors (A) and (B) gives another vector (A + B). i.e

(A + B) = (A) + (B)       ----------------(i)

<em>From the question;</em>

Vector A = 28.0 units in the positive y-direction. This means that the value of the x-component is zero and the value of the y-component is +28

In unit vector notation vector A is given as;

A = 0i + 28.0j

Vector A + B = 19.0 units in the negative y-direction. This means that the value of the x-component is zero and the value of the y-component is -19.0

In unit vector notation, vector A + B is given as;

A + B = 0i - 19.0j

To get the magnitude of vector B, make B the subject of the formula in equation (i) as follows;

(B) = (A + B) - (A)            ------------------ (ii)

Substitute the values of the vectors (A) and (A + B) into equation (ii) as follows;

(B) = (0i - 19.0j) - (0i + 28.0j)

(B) = - 19.0j - 28.0j

(B) = - 47.0j

The magnitude of B, |B|, is therefore;

|B| = |-47.0|

|B| = 47.0 units

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<u>Answer</u>

a) properties and hazards

<u>Explanation</u>

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Most chemicals are very reactive. So you have to be away of their hazards to avoid accidents.


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Given that average speed is distance traveled divided by time, determine the values of m and n when the time it takes a beam of
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Answer:

5,2

Explanation:

From the question we are told that:

Speed of light C=3.0×10^8 m/s.

Generally the equation for Average Speed is mathematically given by

V_{avg}=\frac{d}{t}

Where

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d=1.5*10^11m

Therefore

t=\frac{d}{V_{avg}}

t=\frac{1.5*10^11m}{3.0×10^8 m/s.}

t=5*10^2s

Since m and n is given in the form of

m*10^n

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3 0
3 years ago
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Given the vector A with components Ax = 2.00, Ay = 6.00, the vector B with components Bx = 2.00, By = 22.00, and the vector D =
nekit [7.7K]

Answer:

<em>The magnitude of vector d is 16 and the angle with the x-axis is 270°</em>

Explanation:

<u>Operations With Vectors</u>

Given two vectors in rectangular components:

\vec a=(ax,ay)\ ,\  \vec b=(bx,by)

The sum of the vectors is:

\vec a+\vec b=(ax+bx,ay+by)

The difference between the vectors is:

\vec a-\vec b=(ax-bx,ay-by)

The magnitude of \vec a is:

|\vec a|=\sqrt{ax^2+ay^2}

The angle \vec a makes with the horizontal positive direction is:

\displaystyle \tan\theta=\frac{ay}{ax}\\

The question provides the vectors:

\vec a=(2,6)

\vec b=(2,22)

\vec d=\vec a-\vec b

Calculate:

\vec d=(2,6)-(2,22)=(0,-16)

The magnitude of \vec d is:

|\vec d|=\sqrt{0^2+(-16)^2}=\sqrt{0+256}=16

The angle is calculated by:

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The division cannot be calculated because the denominator is zero. We need to estimate the correct angle by looking at the components of the vector. Since the x-coordinate is zero and the y-coordinate is negative, the vector points downwards (south), thus the angle must be -90° or 270° if the range goes from 0° to 360°.

The magnitude of vector d is 16 and the angle with the x-axis is 270°

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