560+ 147= 707
14(40)= 560
14+ 14(1/2)=21
21(7)= 147
What is the answer for what, please ask your question
Answer:
56
Step-by-step explanation:
Complete question:
Z varies jointly with x and y , x=2 and y=2, z=7. Find z when x=4 and y=8 using joint variation . (I need the problem worked out step by step)
If z varies jointly with x, and y, this is expressed as;
z = kxy
If z=7 when x= 2, y= 2
7 = k(2)(2)
7 = 4k
k = 7/4
To get z when x= 4 and y = 8
z = kxy
z =7/4 (4)(8)
z = 7*8
z = 56
Hence the value of z is 56
3xy + 4x -16 ...... I hope that helps .
Answer:
csc^2x
Step-by-step explanation:
It's a trig identity where 1+cot^2x = csc^2x