Question

Just tell me the perimeter and area plz. will mark as brainliest.

Answer 1

Given that the height of the triangle portion of the enclosure is 28 ft and the base is 22 ft, we can find the two outer sides' lengths using Pythagorean Theorem:

$a^2 + b^2 = c^2$

The legs of the right triangle formed by the height, half the base, and one of the outer walls are 28 and 11. So:

$28^2 + 11^2 = c^2$

$784 + 121 = c^2$

$c = \sqrt{905}$  or about 30.08 ft

This is the length of both linear sides of the enclosure.

Next, to find the bottom side's length, we need to figure out half of the circle's circumference. We know that:

$C = 2 \pi r$

So the other side's length is:

$\frac{1}{2} (22) \pi =11 \pi$

Or about 34.56 ft

The perimeter is:

2(30.08) + 34.56 = 94.72 ft

Next, to find the area of the triangle portion of the enclosure, we must use:

$A = \frac{1}{2}bh$

$\frac{1}{2} (22)(28)$ = 308 ft^2

The area of a circle is:

$A = \pi r^2$

So the semi-circle portion of the enclosure has an area of:

$\frac{1}{2} \pi (11)^2 = \frac{121 \pi }{2}$

or about 190.07 ft^2

The total area of:

308 + 190.07 = 498.07 ft^2

Answer 2

Hey there!  :D




I would say that the perimeter is about 94 .2  and the area is about 498. 07





Hope this helps!!!



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