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Hatshy [7]
2 years ago
7

5 points free, good job

Mathematics
1 answer:
Vilka [71]2 years ago
4 0

Answer:

ok, what's the question?

Step-by-step explanation:

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What is the solution to this linear system? Enter a value in each box to create an ordered pair.
Alisiya [41]

Answer:

Solution of the system will be (-3, 6).

Step-by-step explanation:

If a system of linear equations have been given in the question then we can find the solution of the linear equations by solving these equation algebraically.

But when a graph of the system of equation have been given solution of the system is the point of intersections Or common points lying on both the lines.

From the given graph,

Coordinates of the common point of both the lines is (-3, 6).

Therefore, solution of the system will be (-3, 6).

8 0
3 years ago
Read 2 more answers
Please answer all :3
My name is Ann [436]

Answer:

1 - First question = 6.00 | Second Question = 0.06

2 - Didnt know

3 - 1360, from 1.36kg

4 - 0.3175

5 - 20.5

6 - 18

7 - 965606.4

Step-by-step explanation:

sorry I couldn't give you number 2, but here are the rest of the answers

5 0
2 years ago
Anyone able to answer this?
Ksivusya [100]

Answer:

B) (4,5)

Step-by-step explanation:

Hope this helps.. (again)

3 0
2 years ago
Read 2 more answers
Can anyone help me and show me how to get the answer to this problem 54➗6+2(8-3*4)
ss7ja [257]
I hope this helps, I wrote the new equation each time you get a new number and where it should be placed

7 0
3 years ago
Whats the answer to x^3 y^0 z^-2
Elina [12.6K]

Answer:

\frac{x^3}{z^2}

Step-by-step explanation:

There are no given values, therefore we can't determine a definite answer. However, we are able to simplify the expression.

As we all know that any variable or number to the power of 0 is equal to 1. This means that y^0 = 1.

We also know that a negative power can bring the variable down and make it a fraction. This means that z^-^2=\frac{1}{z^2}

Now that we got these two sorted we are able to write it in a simplified form.

Answer: \frac{x^3}{z^2}

5 0
3 years ago
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