Answer: Given:
Initial velocity= 36km/h=36x5/18=10m/s
Final velocity =54km/h=54x5/18=15m/s
Time =10sec
Acceleration = v-u/ t
=15-10/10=5/10=1/2=0.5 m/s2
Distance =s=?
From second equation of motion:
S=ut +1/2 at^2
=10*10+1/2*0.5*10*10
=100+25
=125m
So distance travelled 125m
Hope it helps you
Answer:
a shiny smooth leaf
Explanation:
A shiny smooth leaf will cause specular reflection. Other choices will cause diffused reflection from the surface.
A specular reflection is similar to how a mirror or smooth surface reflects. The incident light is given off as a single ordered reflection from the surface of a body.
For this to occur, the surface incident must be smooth and without rough patterns on it.
A path way with rough rocks, small patch of soil and rough logs will give off diffused reflection
Should be 1.4, I hope this helps you out
Explanation:
By Hooke's Law, Fe = kx.
Since Fe = 1.6N and x = 9.2cm - 8cm = 1.2cm,
k = Fe/x = 1.6N/1.2cm = 1.33N/cm.
Answer:
(a) the tangential speed of a point at the edge is 3.14 m/s
(b) At a point halfway to the center of the disc, tangential speed is 1.571 m/s
Explanation:
Given;
angular speed of the disc, ω = 500 rev/min
diameter of the disc, 120 mm
radius of the disc, r = 60 mm = 0.06 m
(a) the tangential speed of a point at the edge is calculated as follows;
Tangential speed, v = ωr
v = 52.37 rad/s x 0.06 m
v = 3.14 m/s
(b) at the edge of the disc, the distance of the point = radius of the disc
at half-way to the center, the distance of the point = half the radius.
r₁ = ¹/₂r = 0.5 x 0.06 m = 0.03 m
The tangential velocity, v = ωr₁
v = 52.37 rad/s x 0.03 m
v = 1.571 m/s
