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3 years ago

Which multiplier does the word kilo represent? A. 100 B. 1,000 C. `(1)/(100)` D. `(1)/(10)`

Physics

1 answer:

vladimir2022 [97]3 years ago

4 0

Answer:

A. 1,000

Explanation:

Kilo is the prefix for thousands, thus, the multiplier that kilo represents is 1,000

A. 1,000

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An object is 50 cm from a converging lens with a focal length of 40 cm . A real image is formed on the other side of the lens, 2

Leno4ka [110]

Answer:

d) -4.0

Explanation:

The magnification of a lens is given by

$M=-\frac{q}{p}$

where

M is the magnification

q is the distance of the image from the lens

p is the distance of the object from the lens

In this problem, we have

p = 50 cm is the distance of the object from the lens

q = 250 cm - 50 cm is the distance of the image from the lens (because the image is 250 cm from the obejct

Also, q is positive since the image is real

So, the magnification is

$M=-\frac{200 cm}{50 cm}=-4.0$

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3 years ago

A person jumps from the roof of a house 3.5-m high. When he strikes the ground below, he bends his knees so that his torso decel

Korvikt [17]

The force exerted on his torso by his legs during the deceleration is 4365 N.

Explanation:

Mass of the torso m=45kg

Height of the building s=3.5 m

Decelerating distance=0.71 m

when he jumps to the ground, the only acceleration is acceleration due to gravity g

motion1 from top to ground

initial velocity u=0

we have to calculate final velocity v using the following equation of motion.

$v^2-u^2=2gs\\v^2-0^2=2\times 9.8\times3.5=68.6\\v=\sqrt{68.6} \\=8.3$

use height of the building as the distance s as the jump from top to the ground is only described here.

Motion 2 on the ground

v=0

u=8.3(final velocity of motion 1)

The deceleration after striking the ground can be calculated from the equation of motion

$v^2-u^2=2as\\\\a=v^2-u^2/2\times 0.71\\=0^2-8.3^2/0.71=97 m/s^2$

The decelerating distance is used in the place of s since since the motion after hitting the ground is described in this case.

The equation of force is

$F=ma\\=45\times 97=4365 N$

6 0

3 years ago

In which one of the following situations is zero net work done? A) A ball rolls down an inclined plane. B) A physics student str

lidiya [134]

Answer:

Option D

Explanation:

The work done can be given by the mechanical energy used to do work, i.e., Kinetic energy and potential energy provided to do the work.

In all the cases, except option D, the energy provided to do the useful work is not zero and hence work done is not zero.

In option D, the box is being pulled with constant velocity, making the acceleration zero and thus Kinetic energy of the system is zero. Hence work done in this case is zero.

6 0

4 years ago

Read 2 more answers

A student, starting from rest, slides down a water slide. On the way down, a kinetic frictional force (a nonconservative force)

salantis [7]

Answer:

The velocity with which the student goes down the bottom of glide is 12.48m/s.

Explanation:

The Non conservative force is defined as a force which do not store energy or get he energy dissipate the energy from the system as the system progress with the motion.

Given are

mass of the student 73 kg

height of water glide 11.8 m

work done as -5.5*10³ J

Have to find speed at which the student goes down the glide.

According to Law of Conservation of energy,

K.E =P.E+Work Done

mv²/2=mgh +W

Rearranging the above eqn for v

v = √2(gh+W/m)

Substituting values,

V = 12.48 m/s.