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3 years ago

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A 240 m long segment of wire is hanging between 2 transmission lines. What is the total magnetic force only (ignore gravitationa

l force) on this segment of wire if the current in the wire is 500 A and the field strength is 3e-5 T

1 answer:

Delvig [45]3 years ago

7 0

Answer:

<em>7.2 N</em>

Explanation:

length of wire L = 240 m

current I = 500 A

field strength B = 3 x 10^-5 T

magnetic force on a current carrying conductor F is given as

F = BILsin∅

The wires are perpendicular with field therefore sin∅ = sin 90° = 1

therefore,

F = BIL = 3 x 10^-5 X 500 X 240 = 3.6 N

<em>If the wire exists between this two transmission lines, then total magnetic force on the wire = 2 x 3.6 = 7.2 N</em>

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Read 2 more answers

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Answer:

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$x ^ { ^ \to }$ = $- 0.4 \ j \ m$

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$v_{p,i} ^ { ^ \to } = (280 \ i - 350 \ j) \ m/s$

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$L_i ^ { ^ \to } =0.012 ((- \ 0.4 \ j) *(280 \ i - 350 \ j ))$

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$L_f ^ {^ \to} = I \omega { ^ {^ \to} } = 2.6686 \ \omega ^ {^ \to}$

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$L_f ^ {^ \to} = L_i ^ { ^ \to}$

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4 years ago