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vladimir2022 [97]
3 years ago
9

on a Powerline birds can enjoy sitting from one live wire to the other. However,if a person touches it,then the person will die

within split seconds. explain this situation​
Physics
1 answer:
Alika [10]3 years ago
7 0

Answer:

Due to potential difference (elaborated in explanation)

Explanation:

When a bird sits on a power line, its whole body is in contact with the power line. It does not have any contact with the ground or anything at a lower potential. Hence, the current does not flow through the bird's body, because there is no potential difference available as a driving force.

Now, when a person touches the power line his hand is at a higher potential provided by the power line, while the rest of his body is connected to the ground, usually through legs. The current always looks for a path from high potential to low potential. Therefore, the body of the person serves as the path for the current. Heavy current flows through the body and the person dies within split seconds.

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Answer:

curious george tbh

Explanation:

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What is the specific heat of a substance that absorbs 1600 joules of heat when a sample
kramer

Answer:

8.08 J/g °C

Explanation:

Q=m*Cp*ΔT-->

Cp=Q/(m*ΔT) -->

Cp=1600/[18*(31-20)]-->

Cp=8.08 J/g °C

6 0
3 years ago
Why is it necessary to use oil in conjunction with the 100x lens but not the other objectives?
Setler [38]

Because the refractive indexes of the immersion oil and the glass microscope slide are the same; the oil prevents the refraction of the incoming light rays.

An invisible space is present between the slide and the lens that contains air.

When the light rays fall on the slide and lens they might get refracted due to air present between them.

If the rays get refracted then the diameter of the objective lens will expand further.

So in order to prevent the refraction of light, it is very important to lubricate the surface of the lens because without oil the light rays refract from their original path.

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brainly.com/question/5170843

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3 0
2 years ago
If a car's mass is 439 kg, what is its weight on earth?
trasher [3.6K]
The correct answer is B.
8 0
4 years ago
A cannon of mass 5.71 x 103 kg is rigidly bolted to the earth so it can recoil only by a negligible amount. The cannon fires a 7
zheka24 [161]

Answer:

541.14 m/s

Explanation:

We are given that

Mass of cannon=m_1=5.71\times 10^3 kg

Mass of shell,m_2=73.5 kg

Initial velocity of shell,v=547 m/s

We have to find the velocity of shell fired from this loose cannon.

According to law of conservation of momentum

m_1v_1+m_2v_2=m_1u_1+m_2u_2

Initial momentum of system=0

m_1v_1=-m_2v_2

v_1=-\frac{m_2v_2}{m_1}

When the cannon is bolted to the ground then only shell moves and kinetic energy of system equals to kinetic energy of shell

Kinetic energy of shell,K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 73.5(547)^2}=1.09\times 10^7 J

K.E of shell=\frac{1}{2}m_1v^2_1+\frac{1}{2}m_2v^2_2

K.E of shell=\frac{1}{2}m_1(-\frac{m_2v_2}{m_1})^2+\frac{1}{2}m_2v^2_2

K.E of shell=\frac{1}{2}(\frac{m^2_2v^2_2}{m_1}+\frac{1}{2}m_2v^2_2)

2K.E of shell=m_2v^2_2(\frac{m_2}{m_1}+1)

Velocity of shell fired from this loose cannon,v_2=\sqrt{\frac{2k.E}{m_2(\frac{m_2}{m_1}+1)}

v_2=\sqrt{\frac{2\times 1.09\times 10^7}{73.5(\frac{73.5}{5.71\times 10^3}+1)}

v_2=541.14m/s

Hence, the velocity of shell fired from this loose cannon would be 541.14 m/s

5 0
3 years ago
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