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3 years ago

What is the factorization of the trinomial below? 2x^2-16x+30

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

7 0

Answer:

2(x²-8+15)

X1/2=8+-(64-60) /2= 8+-2 /2=

10/2=5 or

6/2=3

So the answer is C. 2(x-3)(x-5)

You might be interested in

Find the rule and nth term for the sequence <br> 4, 7, 10, 13, 16

mariarad [96]

7-4=3
10-7=3
13-10=3
we can see that this is an arithmetic sequence with a difference of 3
the nth term=the first term +(n-1) times the difference
so a(n)=4+3(n-1)

6 0

3 years ago

Show your work please.

Kruka [31]

Answer:

Tauren has 78 keychains

James has 34 keychains

Marcus has 68 keychains

Yahya has 74 keychains

Step-by-step explanation:

I got this answer by doing this:

If Tauren has 78 keychains then its gonna be left like that.

If everybody else has an average of 68 keychains then divide 68 by 2 to get half of what marcus has which equals 34.

Then add the amount of James and marcus keychains which is 68 plus 34 which equals 102, the subtract the 28 because it says Yayha has 28 fewer keychains and that equals 74.

3 0

4 years ago

1) What are the solutions of the equation? x^2 – 3x = 28?<br><br> Asap please . 30 points

Sedbober [7]

2-3x=28
-3x=28-2
-3x=26
X=-26/3

7 0

3 years ago

Read 2 more answers

A bank is offering 3.5% simple interest on a savings account. If you deposit

arsen [322]

Answer: $525

Step-by-step explanation:

The formula for Simple interest is calculated as PRT where

P = Principal = $7500

R = Rate = 3.5%

T = Time = 2 years

Interest = PRT

= 7500 × 3.5% × 2

= 7500 × 0.035 × 2

= $525

5 0

3 years ago

Centerpieces are normally distributed with mean of 30 ounces and standard deviation of 2 ounces. The weights of the shipping box

astraxan [27]

Answer:

0.0901 = 9.01% of packages will incur such a charge

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Sum of normal variables:

When we add normal variables, the mean will be the sum of the means, while the standard deviation is the square root of the sum of the variances.

Centerpieces are normally distributed with mean of 30 ounces and standard deviation of 2 ounces.

This means that $\mu_C = 30, \sigma_C = 2$

The weights of the shipping boxes are normally distributed with mean of 12 ounces and standard deviation of 1 ounce.

This means that $\mu_S = 12, \sigma_S = 1$

Suppose that centerpieces are chosen at random and packed into randomly chosen shipping boxes.

The shipment is given by the centerpice plus the shipping box. So the mean and the standard deviation of the weight are given by:

$\mu = \mu_C + \mu_S = 30 + 12 = 42$

$\sigma = \sqrt{\sigma_C^2 + \sigma_S^2} = \sqrt{2^2 + 1^2} = \sqrt{5} = 2.236$

If a package exceeds 45 ounces, an additional charge is incurred. What is the proportion of packages will incur such a charge

This proportion is 1 subtracted by the pvalue of Z when X = 45. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{45 - 42}{2.236}$

$Z = 1.34$

$Z = 1.34$ has a pvalue of 0.9099

1 - 0.9099 = 0.0901

0.0901 = 9.01% of packages will incur such a charge

7 0

3 years ago