The common multiple for 1/2 1/4 1/6 1/3 and 1/5 would be 60:
2 x 30 = 60
3 x 20 = 60
4 x 15 = 60
5 x 12 = 60
6 x 10 = 60
Answer:
The answer should be 15%
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
given that we roll a fair die repeatedly until we see the number four appear and then we stop.
the number 4 can appear either in I throw, or II throw or .... indefinitely
So X = the no of throws can be from 1 to infinity
This is a discrete distribution countable.
Sample space= {1,2,.....}
b) Prob ( 4 never appears) = Prob (any other number appears in all throws)
=
where n is the number of throws
As n tends to infinity, this becomes 0 because 5/6 is less than 1.
Hence this probability is approximately 0
Or definitely 4 will appear atleast once.
Answer:
15 1/6
Step-by-step explanation:
change -8 2/3 into an improper fraction = -26/3
-4/7v = -26/3
cross-multiply:
3(-4v) = (-26)7
-12v = -182
v = 182/12
v = 15 1/6
Answer:
It is 432
Step-by-step explanation: