X²/9 + y²/16 = 1
The general for mula of an ellipse is:
(x-h)²/a² + (y-k)²/b² = 1. Since h = k = 0, this ellipse
x²/9 + y²/16 = 1
passes by the center O. (Note that a = 3 and b = 4)
Moreover sin b>a so the majore axis is (on the y-axis) and a the minor axis (on the x-axis) [Its shape is as a vertical egg].
On a system of perpendicular axis that intercept in O., take on the x-axis 2 points A & B with respective coordinate A(3.0) and B(-3,0)
On the y-axis your report A'(0,+4) and B'(0,-4). So you have the vertex of the ellipse, then it's easy to draw it
This can be expressed as exponential growth of the form:
f=ir^t, f=final amount, i=initial amount, r=common ratio (rate), t=time
In this case we are given the point (2, 6500) and i=5000 so we can solve for the rate...
6500=5000r^2 divide both sides by 5000
1.3=r^2 take the square root of both sides and note that we know r>0
r=1.3^(1/2) so our equation becomes:
f=5000(1.3)^(1/2)^t and knowing that (a^b)^c=a^(b*c) we can say:
f=5000(1.3)^(t/2) so for t=18
f=5000(1.3)^9
f≈53022 (to nearest whole bacteria)
The balloon reaches a height of 7 feet at 0.1 seconds and 2.13 seconds
<h3>How to determine the time the balloon is at the height?</h3>
The equation of the function is given as
h(t)= -16t^2 + 35t + 5
The above equation is a quadratic equation
When the balloon is at a height of 7 feet, we have
h(t) = 7
So, we have the following equations
h(t)= -16t^2 + 35t + 5
h(t) = 7
Next, we plot the equations on a graph (see attachment)
The equations intersect at
t = 0.059 and t = 2.129
Approximate
t = 0.1 and 2.13
Hence, the times are 0.1 seconds and 2.13 seconds
Read more about quadratic equation at
brainly.com/question/15709421
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Answer:
0.2
Step-by-step explanation:
Multiply 4/5 and 1/4: Decimal form
.8 • .25
Answer:
11,15,19,23,27,31,35,39,43,47,51,....
