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3 years ago

If a ray of light has a wavelength of 580 nanometers, what shade of visible light does it produce?

Physics

1 answer:

diamong [38]3 years ago

4 0

D. yellow

Explanation:

If a ray of light has a wavelength of 580nm, the shade of visible light it will produce is yellow.

Light is a form of electromagnetic radiation that forms a broad spectrum when it passes through a prism.

From the spectrum shown in the diagram, we can easily solve the problem.
The wavelength of a wave is the distance between successive crest and trough on a wave.
Visible light is made up of about seven colors.
Visible light is often seen as white light.
When the colors are resolved, we have the different colors of light.
Yellow in the spectrum is located around wavelength 580nm

learn more:

Electromagnetic radiation brainly.com/question/6818046

#learnwithBrainly

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· List the atomic numbers of the elements in Period 2.

PilotLPTM [1.2K]

Answer:

3,4,5,6,7,8,9,10

3. lithium

4. beryllium

5. boron

6. carbon

7. nitrogen

8. oxygen

9. fluorine

10. neon

those are the numbers in period 2 on the periodic table.

Explanation:

4 0

3 years ago

Read 2 more answers

A 25.0 kg child slides down a long slide in a playground. She starts from rest at a height h1 of 21.00 m. When she is partway do

____ [38]

Answer:

The mechanical energy lost due to friction is 2,424.5 J

Explanation:

Given;

mass of the child, m = 25 kg

intial velocity of the child, u = 0

final velocity of the child, v = 7.8 m/s

initial position of the child, h₁ = 21 m

final position of the child, h₂ = 8 m

Let the energy lost due to heat = ΔE

ΔE + ΔK.E + ΔP.E = 0

ΔE + ¹/₂m(v² - u²) + mg(h₂ - h₁) = 0

ΔE + ¹/₂ x 25(7.8² - 0) + 25 x 9.8(8 - 21) = 0

ΔE + 760.5 J - 3185 J =

ΔE - 2,424.5 J = 0

ΔE = 2,424.5 J

Therefore, the mechanical energy lost due to friction is 2,424.5 J

4 0

3 years ago

In Houston, Earth's B→ field has a magnitude of 5.2 × 10−5 Tand points in a direction 57∘ below a horizontal line pointing north

Anastasy [175]

Answer:

F = 0.0034 N

Explanation:

Given:

$B = 5.2*10^(-5) T\\Q = 57 degrees\\I_{wire} = 12 A\\L_{wire} = 10 m$

The angle between B and wire = 90 - 57 = 33 degrees

Using formula:

$F = B*I*L*sin (90-Q)\\F = (5.2*10^(-5)*(12)*(10)*sin (33)\\F = 0.0034 N$

6 0

3 years ago

A Block slides down an incline that makes an angle of 30? with the horizontal direction. The coefficient of kinetic friction bet

astraxan [27]

Answer:

Acceleration = 2.35 m/ $s^{2}$

Speed = 8.67 m/s

Explanation:

The coefficient of friction , u =0.3

The angle of incline = 30°

The two forces acting on block are weight and friction.

weight along the incline = mg cos60° = $\frac{mg}{2}$ = 0.5 mg

Friction along incline = umg cos30° = mg $0.3\times \frac{\sqrt{3}}{2}$

Friction along incline = 0.26 mg

Net force acting on the weight = (0.5 - 0.26) mg = 0.24 mg

Acceleration = $\frac{net force}{mass}$ = 0.24 g = 2.35 m/ $s^{2}$

The height of incline = 8 m

Length of the inclined edge = 16 m

$v^{2}=u^{2}+2as$

$v^{2}= 2\times 0.24 \times 9.8\times 16$

v= 8.67 m/s

5 0

4 years ago

Find the acceleration of the blocks when the system is released. The coefficient of kinetic friction is 0.4, and the mass of eac

grin007 [14]

Answer:

a = 4.9(1 - sinθ - 0.4cosθ)

Explanation:

Really not possible without a complete setup.

I will ASSUME that this an Atwood machine with two masses (m) connected by an ideal rope passing over an ideal pulley. One mass hangs freely and the other is on a slope of angle θ to the horizontal with coefficient of friction μ. Gravity is g

F = ma

mg - mgsinθ - μmgcosθ = (m + m)a

mg(1 - sinθ - μcosθ) = 2ma

½g(1 - sinθ - μcosθ) = a

maximum acceleration is about 2.94 m/s² when θ = 0

acceleration will be zero when θ is greater than about 46.4°

8 0

3 years ago