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raketka [301]
3 years ago
10

In Houston, Earth's B→ field has a magnitude of 5.2 × 10−5 Tand points in a direction 57∘ below a horizontal line pointing north

.Part ADetermine the magnitude of the magnetic force exerted by the magnetic field on a 11-m-long vertical wire carrying a 11-A current straight upward. Express your answer to two significant figures and include the appropriate units.Part BDetermine the direction of the magnetic force.a. to the northb. to the eastc. to the southd. to the west
Physics
1 answer:
Anastasy [175]3 years ago
6 0

Answer:

F = 0.0034 N

Explanation:

Given:

B = 5.2*10^(-5) T\\Q = 57 degrees\\I_{wire} = 12 A\\L_{wire} = 10 m

The angle between B and wire = 90 - 57 = 33 degrees

Using formula:

F = B*I*L*sin (90-Q)\\F = (5.2*10^(-5)*(12)*(10)*sin (33)\\F = 0.0034 N

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Answer:

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Given data

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we know weight = mg and buoyant force = water density × g

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and

weight of anchor is mg

here mass m = density Fe g

density Fe = 7870 from table 14-1

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4 years ago
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Answer:

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