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ANTONII [103]
4 years ago
12

Write the sentence as an inequality The sum of twice a number n and 8 is at most 25

Mathematics
2 answers:
Yakvenalex [24]4 years ago
7 0
2n+8≥25
Hope this could help
Marta_Voda [28]4 years ago
5 0

2n  + 8  \leqslant 25
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PLEASE!!! I NEED HELP WITH THIS ASAP!!!
MrRa [10]
Part 1
Total paid
=cost of the bond+commission
Total paid
32×96.7+32×10=3,414.4

Part 2
Annual interest
32×96.7
=3,094.4
3,094.4×0.08625
=266.892...Annual interest

Part 3
The effective interest rate
((1+0.08625÷12)^(12)−1)×100
=8.974%
6 0
4 years ago
Give the coordinates of each transformation of (2, –3)
Nadusha1986 [10]

Answer:

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Last year, Edward spent a total of $626.14 on his power bill. Rounding the total bill to the nearest tens place, approximate how
zlopas [31]

Answer:

He spent around  $ 52.17  in each month.

Step-by-step explanation:

Last year the power bill price = $ 626.14 ≈  $ 626

We know that in a year 12 months. so power bill of each month in last year is calculated as follows

Power \ bill \ of \ each \ month = \frac{Total \ bill \ of  \ the \ year}{12}

Power \ bill \ of \ each \ month = \frac{626}{12}

Power \ bill \ of \ each \ month =  $ 52.17

Therefore he spent around  $ 52.17  in each month.

7 0
4 years ago
Plss help me!!
lakkis [162]

Step-by-step explanation:

The problem statement says λ<1.  If this is true, then the cannonball is slower than the boat, and it will never reach the boat.  So I assume it's actually λ>1.

If we say t is the amount of time, then the boat travels south a distance of ut, and the cannonball travels a distance of λut.

v = λut

ut = v/λ

Using Pythagorean theorem:

d² + (ut)² > v²

d² + (v/λ)² > v²

λ²d² + v² > λ²v²

λ²d² > (λ² − 1) v²

λ² / (λ² − 1) > (v/d)²

4 0
3 years ago
Complete the following item based on the given information. The volume of a box(V) varies directly with its length(l). If a box
bija089 [108]

Step-by-step explanation:

Below is an attachment containing the solution.

6 0
3 years ago
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