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Dennis_Churaev [7]
3 years ago
5

What is 4 square root 7^3 in exponential form?

Mathematics
2 answers:
Gnesinka [82]3 years ago
8 0

Answer:

Given the radical form: 4\sqrt{7^3}

Use the exponent rules:

\sqrt[n]{a^m} = (a^m)^{\frac{1}{n}} = a^{\frac{m}{n}}

we can write \sqrt{7^3} as:

\sqrt{7^3} = (7^3)^{\frac{1}{2}} = 7^{\frac{3}{2}}

then;

4\sqrt{7^3} = 4 \cdot 7^{\frac{3}{2}}

Therefore, 4\sqrt{7^3} in exponential form is 4 \cdot 7^{\frac{3}{2}}


anastassius [24]3 years ago
6 0

Answer:

on edgen its A.)<em> 7 3/4</em>

Step-by-step explanation:


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Step-by-step explanation:

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Hope this helps!

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What is the sum or difference of 7/8 - 3/8 and the simplest form of it.
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The answer will be 4/8 but the simplest form is 1/2
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3 years ago
Help me to prove the given below. Thank you in advance
sleet_krkn [62]

Answer:

Construct MO, where O is the midpoint of CG. (As shown in the attached figure)

(1) LM = MG //given, CM is the median to the hypotenuse      

(2) CO = OG // construction    

(3) MO is a mid-segment   //(1), (2) , Definition of a mid-segment

(4) MO // LC //triangle mid-segment theorem    

(5) ∠MOG ≅ ∠LCO // corresponding angles in two parallel lines intersected by a transversal line (CG)

(6) m∠LCO=90°  //given, ΔLCG is a right triangle

(7) m∠MOG=90° //(5), (6), definition of congruent angles

(8) m∠MOC=180° – 90° = 90° // linear pair

(9) ∠MOG ≅ ∠MOC //(7),(8), definition of congruent angles

(10) MO=MO //common side, reflexive property of equality  

(11) ΔMCO ≅ ΔMGO  //(2), (9), (10) Side-Angle-Side postulate

(12) MC = MG // Corresponding sides in congruent triangles (CPCTC)      

(13) MG= ½LG // Given, CM is the median to the hypotenuse    

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8 0
3 years ago
6th grade mathematics<br> Find the number that makes the ratio equivalent to 40:16<br><br><br> 5:
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Answer:

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Step-by-step explanation:

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hope this helps you!!

4 0
2 years ago
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