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Marat540 [252]
3 years ago
5

When you jump upward, your hang time is the time your feet are off the ground. Does hang time depend on the vertical component o

f velocity when you jump, the horizontal component of velocity, or both? 1. Both components 2. The horizontal component of your lift-off velocity 3. The vertical component of your lift-off velocity 4. Unable to determine
Physics
1 answer:
hjlf3 years ago
7 0

Answer:

It only depends on the vertical component

Explanation:

Hello!

The horizontal component will tell you how much you travel in that direction.

You could have a large horizontal velocity, but if the vertical velocity is zero, you will never be out of the ground. Similarly, you could have a zero horizontal velocity, but if you have a non-zero vertical velocity you will be some time off the ground. This time can be calculated by two means, one is using the equation of motion (position as a function of time) and the other using the velocity as a fucntion of time.

For the former you must find the time when the position is zero.

Lets consider the origin of teh coordinate system at your feet

y(t) = vt - (1/2)gt^2

We are looking for a time t' for which y(t')=0

0 = vt' - (1/2)gt'^2

vt' = (1/2)gt'^2

The trivial solution is when t'=0 which is the initial position, however we are looking for t'≠0, therefore we can divide teh last equation by t'

v = (1/2)gt'

Solving for t'

t' = (2v/g)

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