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Ira Lisetskai [31]
3 years ago
14

You should be able to use the speed of our fastest interplanetary spacecraft, and calculate the time in Days, it would take to t

ravel to the planet Mars. For our purposes, this means you would need to travel 58 Million Kilometers. Show all work for on calculations for any credit.
Physics
1 answer:
Paul [167]3 years ago
8 0
I think it would be 218 days!
You might be interested in
A gas expands and does PV work on its surroundings equal to 319 J. At the same time, it absorbs 136 J of heat from the surroundi
LiRa [457]

Answer:

The change in energy of the gas during the process is -1.83\times 10^{2} joules.

Explanation:

We can represent this process by the First Law of Thermodynamics, in which gas does work on its surroundings and absorbs heat from there to describe its change in energy. In other words:

Q_{in} - W_{out} = \Delta E

Where:

Q_{in} - Heat absorbed by the gas, measured in joules.

W_{out} - Work done by the gas, measured in joules.

\Delta E - Change in energy, measured in joules.

If we know that Q_{in} = 1.36\times 10^{2}\,J and W_{out} = 3.19\times 10^{2}\,J, the change in energy of the gas is:

\Delta E = 1.36\times 10^{2}\,J-3.19\times 10^{2}\,J

\Delta E = -1.83\times 10^{2}\,J

The change in energy of the gas during the process is -1.83\times 10^{2} joules.

3 0
3 years ago
) It is necessary to maintain a constant fluid volume in the body. Therefore, the body adjusts the water outputs to be equal to
loris [4]

Answer:

Evaporative Water Loss = 2 kg

Explanation:

According to the given condition, the water entering the body must be equal to the water leaving the body. Therefore,

Water Entering the Body = Water Leaving the Body

Feed Water + Drinking Water + Metabolic Water = Urine Water + Evaporative Water Loss

using the given values:

1 kg + 5 kg + 0.5 kg = 4.5 kg + Evaporative Water Loss

Evaporative Water Loss = 1 kg + 5 kg + 0.5 kg - 4.5 kg

<u>Evaporative Water Loss = 2 kg</u>

8 0
2 years ago
the net external force on the 24-kg mower is stated to be 51 N. If the force of friction opposing the motion is 24 N, what force
-Dominant- [34]

Answer:

PART A)

External force will be 75 N

PART B)

distance moved will be 1.125 m

Explanation:

PART A)

Given that net force on the mower is

F_{net} = 51 N

now we also know that friction force due to ground is given as

F_f = 24 N

now we have

F_{net} = F_{ext} - F_f

51 = F_{ext} - 24

F_{ext} = 75 N

so external force will be 75 N

PART B)

deceleration due to friction when external force is removed from it

a = \frac{F_f}{m}

a = \frac{24}{24} = 1 m/s^2

now we can find the distance by kinematics

v_f^2 - v_i^2 = 2 a d

0 - 1.5^2 = 2(-1)d

d = 1.125 m

so the distance moved will be 1.125 m

6 0
3 years ago
Lexy throws a dart with an initial velocity of 25 m/s at an angle of 60° relative to the ground. what is the approximate vertica
Serjik [45]
An initial velocity is:
v o = 25 m/s
The vertical component of the initial velocity:
v o y = v o * sin 60° =
= v o * √3 / 2 = 25 m/s * √3 / 2 = 21.65 m/s
Answer:
The approximate vertical component of the initial velocity is 21.65 m/s.
7 0
3 years ago
Read 2 more answers
ALL OF MY POINTS FOR THIS!
scoray [572]
Newton's 2nd law of motion:

                       Force  =  (mass) x (acceleration)

                                   =  (1,127 kg) x (6 m/s² forward)

                                   =  (1,127 x 6)  newtons forward

                                   =    6,762 newtons forward
______________________________

             Momentum  =  (mass) x (speed)

                                 =   (69 kg) x (6 m/s)

                                 =      414 kg-m/s
3 0
3 years ago
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