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sattari [20]
2 years ago
10

What is the slope of the line if the rise of a line on a distance versus-time graph is 900 meters and the run is 3 minutes?

Physics
1 answer:
Alexandra [31]2 years ago
6 0
600/3 = 200
the slope is 200m/min
 
OR

600/ (3/60) =
600 x 60/3 =
600 x 20 = 12,000 meters per hour 

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In an attempt to escape his island, Gilligan builds a raft and sets to sea. The wind shifts a great deal during the day, and he
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Answer:8.28 km

Explanation:  

Given

First it drifts 45^{\circ} 2.5 km

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Secondly it drifts 60^{\circ} 4.70 km

r_{12}=4.7cos60 i-4.7sin60 j

After that it drifted along east direction 5.1 km

r_{23}=5.1 i

After that it drifts 55^{\circ} 7.2 km

r_{34}=-7.2cos55 i-7.2sin55 j

After that it drifts 5^{\circ} 2.8 km

r_{54}=-2.8cos5 i+2.8sin5 j

r_{5O}=\left [ 2.5cos45+4.7cos60+5.1-7.2cos55-2.8cos5\right ]\hat{i}+\left [ 2.5sin45-4.7sin60-7.2sin55+2.8sin5\right ]\hat{j}

r_{5O}=2.299\hat{i}-7.95\hat{j}

|r_{5O}|=8.28 km

for direction

tan\theta =\frac{7.95}{2.299}=3.4580

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7 0
3 years ago
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50 POINTS HELP ME PLEASE!!!!!!!!!!!!
Mariana [72]

Answer:

W and X

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When escaping a rip current, one should always walk to the side until you escape from the rip current. If you walk towards the shore, you have the ability to keep getting dragged toward the current, such as with X and Y.

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During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approxima
vova2212 [387]

Answer:

The value  F  =  0.1396 \ N

Explanation:

From the question we are told that

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    The velocity of the blood ejected is  v  = 103 \  cm/s  = \frac{103}{100} = 1.03 \ m/s

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The average force exerted by the blood on the wall of the aorta is mathematically represented as

      F  =  2 * \rho  *  V  *  R *  v

=>    F  =  2 * 1060  *  65*10^{-6}  *  0.9833 *  1.03

=>    F  =  0.1396 \ N

8 0
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What do we call the distance labeled from A to B and what could we do to the note played on an instrument to change that distanc
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Correct answer choice is :


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Explanation:


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