So you would first multiply 400 by 2 which equals 800, then add 30 which is 830.
Then you would subtract 1000-830=170.
The total force of the 6 other players would be 170N.
Hoped this helped ☺️
Answer:
The distance between two posts
Explanation:
As the students have already measured the amount of time necessary for the wave to oscillate up and down that is on the string between two posts,They have to measure the speed of the wave.
ie v=fλ
<em>They have to measure distance between the posts.
</em>
Because wavelength is equal to the distance between the posts ie full length of string.
The frequency of the wave is calculated by
f=
1/T
Where is the time period which the students have calculated ie the amount of time taken to oscillate up and down,
Thus the wave speed is calculated using formula
v=λ/T
Answer:
The dog has more momentum than the pony.
Explanation:
To solve this problem, we must remember the formula for calculating momentum, which is given below:
momentum = p = m*v
where m represents the mass of the object and v represents the velocity of the object
Using this knowledge, let's calculate the momentum for the dog and the pony.
Dog: p = m*v = (2kg)*(41 m/s) = 82 kg*m/s
Pony: p = m*v = (75kg)*(1 m/s) = 75 kg*m/s
Since 82 > 75, we can conclude that the dog has more momentum.
Hope this helps!
Answer:
The correct answer is
p = p₁ + p₂
Explanation:
Newton's second law states that force = the change of momentum produced therefore since the collision is inelstic then the change of momentum of each car is p₁ and p₂ and the force of the collition is proportional to p₁ + p₂ that is
F ∝ p₁ + p₂ and since force is directly proportional to p we have
p = p₁ + p₂
Answer:
165.8 V/m
Explanation:
The capacitance of a long concentric cylindrical shell of length, L and inner radius, a and outer radius, b is C = 2πε₀L/㏑(b/a)
Since the charge on the cylindrical shells, Q = CV where V = the potential difference across the capacitor(which is the potential difference between the concentric cylindrical shells)
V = Q/C
V = Q ÷ 2πε₀L/㏑(b/a)
V = Q㏑(b/a)/2πε₀L
So, the potential difference per unit length V' is
V' = V/L = Q㏑(b/a)/2πε₀
Given that a = inner radius = 1.5 cm, b = outer radius = 5.6 cm and Q = 7.0 nC = 7.0 × 10⁻⁹ C and ε₀ = 8.854 × 10⁻¹² F/m substituting the values of the variables into the equation, we have
V' = Q㏑(b/a)/2πε₀
V' = 7.0 × 10⁻⁹ C㏑(5.6 cm/1.5 cm)/(2π × 8.854 × 10⁻¹² F/m)
V' = 7.0 × 10⁻⁹ C㏑(3.733)/(55.631 × 10⁻¹² F/m)
V' = 7.0 × 10⁻⁹ C × 1.3173/(55.631 × 10⁻¹² F/m)
V' = 9.2211 × 10⁻⁹ C/(55.631 × 10⁻¹² F/m)
V' = 0.16575 × 10³ V/m
V' = 165.75 V/m
V' ≅ 165.8 V/m