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meriva
4 years ago
15

7. For a constant force, suppose the duration of

Physics
1 answer:
lara [203]4 years ago
8 0

a. impulse increases by the square of the force.

b. momentum also increases

Explanation:

  • As we know, force is defined as the product of mass and acceleration of the object. Impulse is nothing but the impulse of an object moving is defined as the integral of all the forces acting on the object.
  • As we know that force is a vector quantity and hence the impulse. Since impulse is the integral of all the forces. Here, in the question, it is given that the force is doubled then if you integrate then you get a square function. So, the impulse increases by square function.
You might be interested in
PLEASE HELP!
WINSTONCH [101]
So you would first multiply 400 by 2 which equals 800, then add 30 which is 830.
Then you would subtract 1000-830=170.
The total force of the 6 other players would be 170N.
Hoped this helped ☺️
7 0
3 years ago
A string is vibrating between two posts as shown above. Students are to determine the speed of the wave within this string. They
kow [346]

Answer:

The distance between two posts

Explanation:

As the students have already measured the amount of time necessary for the wave to oscillate up and down that is on the string between two posts,They have to measure the speed of the wave.

        ie  v=fλ

<em>They have to measure distance between the posts. </em>

Because wavelength is equal to the distance between the posts ie full length of string.

The frequency of the wave is calculated by

               f= 1/T

Where is the time period which the students have calculated ie the amount of time taken to oscillate up and down,

Thus the wave speed is calculated using formula

            v=λ/T

6 0
3 years ago
Which has more momentum, a 2.0 kg dog at 41 m/s or a 75 kg pony at 1.0 m/s?
Nesterboy [21]

Answer:

The dog has more momentum than the pony.

Explanation:

To solve this problem, we must remember the formula for calculating momentum, which is given below:

momentum = p = m*v

where m represents the mass of the object and v represents the velocity of the object

Using this knowledge, let's calculate the momentum for the dog and the pony.

Dog: p = m*v = (2kg)*(41 m/s) = 82 kg*m/s

Pony: p = m*v = (75kg)*(1 m/s) = 75 kg*m/s

Since 82 > 75, we can conclude that the dog has more momentum.

Hope this helps!

3 0
4 years ago
Two cars collide inelastically and stick together after the collision. Before the collision, the magnitudes of their momenta are
slavikrds [6]

Answer:

The correct answer is

p = p₁ + p₂

Explanation:

Newton's second law states that force = the change of momentum produced therefore since the collision is inelstic then the change of momentum of each car is p₁ and  p₂ and the force of the collition is proportional to p₁ + p₂ that is

F ∝ p₁ + p₂ and since force is directly proportional to p we have

p = p₁ + p₂

7 0
4 years ago
What is the potential difference per unit length between two infinitely long concentric cylindrical shells with inner radius 1.5
Vinil7 [7]

Answer:

165.8 V/m

Explanation:

The capacitance of a long concentric cylindrical shell of length, L and inner radius, a and outer radius, b is C = 2πε₀L/㏑(b/a)

Since the charge on the cylindrical shells, Q = CV where V = the potential difference across the capacitor(which is the potential difference between the concentric cylindrical shells)

V = Q/C

V = Q ÷ 2πε₀L/㏑(b/a)

V = Q㏑(b/a)/2πε₀L

So, the potential difference per unit length V' is

V' = V/L = Q㏑(b/a)/2πε₀

Given that a = inner radius = 1.5 cm, b = outer radius = 5.6 cm and Q = 7.0 nC = 7.0 × 10⁻⁹ C and ε₀ = 8.854 × 10⁻¹² F/m substituting the values of the variables into the equation, we have

V' = Q㏑(b/a)/2πε₀

V' = 7.0 × 10⁻⁹ C㏑(5.6 cm/1.5 cm)/(2π × 8.854 × 10⁻¹² F/m)

V' = 7.0 × 10⁻⁹ C㏑(3.733)/(55.631 × 10⁻¹² F/m)

V' = 7.0 × 10⁻⁹ C × 1.3173/(55.631 × 10⁻¹² F/m)

V' = 9.2211 × 10⁻⁹ C/(55.631 × 10⁻¹² F/m)

V' = 0.16575 × 10³ V/m

V' = 165.75 V/m

V' ≅ 165.8 V/m

6 0
3 years ago
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