Answer:
Explanation:
Given
mass of hot metal ![m_1=0.06\ kg](https://tex.z-dn.net/?f=m_1%3D0.06%5C%20kg)
specific heat ![c=889\ J/kg-^{\circ}C](https://tex.z-dn.net/?f=c%3D889%5C%20J%2Fkg-%5E%7B%5Ccirc%7DC)
mass of water ![m_2=0.16\ kg](https://tex.z-dn.net/?f=m_2%3D0.16%5C%20kg)
Temperature pf water ![T_2=20^{\circ}C](https://tex.z-dn.net/?f=T_2%3D20%5E%7B%5Ccirc%7DC)
Final Temperature ![T=25^{\circ}C](https://tex.z-dn.net/?f=T%3D25%5E%7B%5Ccirc%7DC)
let
be the temperature of hot metal ball
Heat lost by heat metal bolt is gained by water in calorimeter
Heat lost by hot metal bolt ![Q_1=m\times c\times \Delta T](https://tex.z-dn.net/?f=Q_1%3Dm%5Ctimes%20c%5Ctimes%20%5CDelta%20T)
![Q_1=0.06\times 889\times (T-25)](https://tex.z-dn.net/?f=Q_1%3D0.06%5Ctimes%20889%5Ctimes%20%28T-25%29)
Heat gained by water ![Q_2=m_2\times c_w\times \Delta T](https://tex.z-dn.net/?f=Q_2%3Dm_2%5Ctimes%20c_w%5Ctimes%20%5CDelta%20T)
![Q_2=0.16\times 4184\times (25-20)](https://tex.z-dn.net/?f=Q_2%3D0.16%5Ctimes%204184%5Ctimes%20%2825-20%29)
![Q_1=Q_2](https://tex.z-dn.net/?f=Q_1%3DQ_2%20)
![0.06\times 889\times (T-25)=0.16\times 4184\times (25-20)](https://tex.z-dn.net/?f=0.06%5Ctimes%20889%5Ctimes%20%28T-25%29%3D0.16%5Ctimes%204184%5Ctimes%20%2825-20%29)
![T_1=25+62.75](https://tex.z-dn.net/?f=T_1%3D25%2B62.75)
![T_1=87.75^{\circ}C](https://tex.z-dn.net/?f=T_1%3D87.75%5E%7B%5Ccirc%7DC)
Answer:
8 units
Explanation:
F=(k*q1*q2)/(r^2)
K is a constant, q1 is charge of 1, q2 is charge of 2, r is distance between the two.
Answer:
The answer is ( D) i. e both b and c.