Well I figured out at his current pace, he would finish the 1100 remaining meters in 200 seconds. However, he needs to complete it in 180 seconds. I'm not sure how to find out how long he has to accelerate at 0.20 m/s/s to complete it in 180 seconds.

3 0

3 years ago

A(n) 1100 kg car is parked on a 4◦ incline. The acceleration of gravity is 9.8 m/s 2 . Find the force of friction keeping the ca

igomit [66]

Answer:

Force of friction, f = 751.97 N

Explanation:

it is given that,

Mass of the car, m = 1100 kg

It is parked on a 4° incline. We need to find the force of friction keeping the car from sliding down the incline.

From the attached figure, it is clear that the normal and its weight is acting on the car. f is the force of friction such that it balances the x component of its weight i.e.

$f=mg\ sin\theta$

$f=1100\ kg\times 9.8\ m/s^2\ sin(4)$

f = 751.97 N

So, the force of friction on the car is 751.97 N. Hence, this is the required solution.

3 0

3 years ago

LetterA., please see attachment

Anika [276]

The air of atmosphere contains oxygen which helps us in breathing and digestion and respiration of food
The nitrogen in air is helpful for plants and fertilizers
The humidity or water in atmosphere helps in rain

7 0

3 years ago

Read 2 more answers

Physics question plz help

blagie [28]

Answer:

B. $30\,s\,< t \le 40\,s$ .

Explanation:

The vehicle is travelling eastwards when its velocity is positive and westwards when velocity is negative. According to the graph, $v > 0$ for $30\,s\,< t \le 40\,s$ . Hence, correct answer is B.

5 0

3 years ago