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maks197457 [2]
3 years ago
9

A stationary source S generates circular outgoing waves on a lake. The wave speed is 5.0 m/s and the crest-to-crest distance is

2.0 m. A person in a motorboat heads directly toward S at 3.0 m/s. To this person, the frequency of these waves is:
Physics
1 answer:
Aleonysh [2.5K]3 years ago
4 0

Answer:4 Hz

Explanation:

Speed of wave v=5 m/s

crest to crest distance \lambda =2 m

velocity of observer v_0=3 m/s

actual frequency f=\frac{velocity}{\lambda }

f=\frac{5}{2}=2.5 Hz

Apparent frequency f'=f(\frac{v+v_0}{v})

f'=2.5\times \frac{5+3}{5}

f'=4 Hz      

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A sled slides along a horizontal surface on which the coefficient of kinetic friction is 0.25. Its velocity at point A is 8.6 m/
jenyasd209 [6]

Answer:

\Delta t =1.31\ s

Explanation:

given,

coefficient of kinetic friction, μ = 0.25

Speed of sled at point A = 8.6 m/s

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time taken to travel from point A to B.

we know,

J = F Δ t

J is the impulse

where  F is the frictional force.

t is the time.

we also know that impulse is equal to change in momentum.

J = m(v_f - v_i)

frictional force

F = μ N

where as N is the normal force

now,

F\Delta t = m(v_f -v_i)

\mu m g \times \Delta t = m(v_f-v_i)

\mu g \times \Delta t = v_f-v_i

\Delta t =\dfrac{v_f-v_i}{\mu g}

\Delta t =\dfrac{8.6-5.4}{0.25\times 9.8}

\Delta t =1.31\ s

time taken to move from A to B is equal to 1.31 s

3 0
4 years ago
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You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this state
Aleks04 [339]

Explanation:

It is given that,

Height of the building, h = 44 m

Initial horizontal velocity, u_x=ucos\theta=8.6\ m/s

Initial vertical velocity, u_y=usin\theta=10.5\ m/s

It can be assumed to find the maximum height of the projectile and time taken to reach the maximum height.

The formula for the maximum height is given by :

H=\dfrac{(u\ sin\theta)^2}{2g}

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H=\dfrac{(10.5)^2}{2\times 9.8}=5.625\ m

The total maximum height, h' = h + H

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The formula for the time of flight is given by :

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t_{max}=\dfrac{10.5}{9.8}=1.07\ s

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3 0
3 years ago
Radio waves travel at the speed of light, which is 3.00 u 108 m/s. How many kilometers will radio messages travel in exactly one
egoroff_w [7]

Answer:                

Distance traveled will be 9.462\times 10^{12}km

Explanation:

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We know that 1 year = 8760 hour

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8 0
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You want a special device to keep coffee warm what type of electromagnetic waves would be useful
fredd [130]
Microwaves at the specific frequency where vibrates water molecules

Or

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8 0
4 years ago
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Gnom [1K]

Answer: The first one

Explanation:

Because it’s the higher frequency

4 0
3 years ago
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