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maks197457 [2]
3 years ago
9

A stationary source S generates circular outgoing waves on a lake. The wave speed is 5.0 m/s and the crest-to-crest distance is

2.0 m. A person in a motorboat heads directly toward S at 3.0 m/s. To this person, the frequency of these waves is:
Physics
1 answer:
Aleonysh [2.5K]3 years ago
4 0

Answer:4 Hz

Explanation:

Speed of wave v=5 m/s

crest to crest distance \lambda =2 m

velocity of observer v_0=3 m/s

actual frequency f=\frac{velocity}{\lambda }

f=\frac{5}{2}=2.5 Hz

Apparent frequency f'=f(\frac{v+v_0}{v})

f'=2.5\times \frac{5+3}{5}

f'=4 Hz      

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A hiker walks 9.4 miles at an angle of 60° south of west. Find the west and south components of the walk. Round your answers to
Tanzania [10]

Answer:

The west axis component of walk is, A = 5 miles

The east axis component of walk is, B = 8 miles

Explanation:

Given data,

The displacement of hiker south of west, R = 9.4 miles

The angle formed south of west, Ф = 60°

The vector components along,

                   the west axis is

                                      A = R cosФ

                                       A = 9.4 x cos 60

                                       A = 4.7 miles

                                        A = 5 miles

The west axis component of walk is, A = 5 miles

                    the south axis is

                                      B = R sinФ

                                       B = 9.4 sin 60

                                        B = 8.14 miles

                                         B = 8 miles

The east axis component of walk is, B = 8 miles

4 0
3 years ago
A magnetic B field of strength 18 T is perpendicular to a conducting loop of wire measuring 0.9 square meters with 30 turns. If
Murljashka [212]

Answer:

magnitude of the induced emf voltage = 121.5 V

Explanation:

given data

magnetic field of strength B =  18 T

area = 0.9 m²

no of turn = 30 turns

Δt = 4s

to find out

magnitude of the induced emf voltage

solution

we get her magnitude of the induced emf voltage that is express as

magnitude of the induced emf voltage = \frac{d\phi}{dt}   ......1

magnitude of the induced emf voltage = n*a * \frac{dB}{dt}

magnitude of the induced emf voltage = 30* 30* \frac{18}{4}

magnitude of the induced emf voltage = 121.5 V

7 0
3 years ago
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