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maks197457 [2]
3 years ago
9

A stationary source S generates circular outgoing waves on a lake. The wave speed is 5.0 m/s and the crest-to-crest distance is

2.0 m. A person in a motorboat heads directly toward S at 3.0 m/s. To this person, the frequency of these waves is:
Physics
1 answer:
Aleonysh [2.5K]3 years ago
4 0

Answer:4 Hz

Explanation:

Speed of wave v=5 m/s

crest to crest distance \lambda =2 m

velocity of observer v_0=3 m/s

actual frequency f=\frac{velocity}{\lambda }

f=\frac{5}{2}=2.5 Hz

Apparent frequency f'=f(\frac{v+v_0}{v})

f'=2.5\times \frac{5+3}{5}

f'=4 Hz      

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The total work done is 957.56 joules. This is calculated as work is equal to 25N time 50 meters time cosine 40 degrees.
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The heat flux for a given wall is in the x-direction and given as q^n = 11 W/m^2, the walls thermal conductivity is 1.7 W/mK and
MrMuchimi

Answer:

\frac{dT}{dx} = 6.47 ^oC/m

Also as we can see the equation that heat flux directly depends on the temperature gradient so more is the temperature gradient then more will be the heat flux.

For positive temperature gradient the heat will flow outwards while for negative temperature gradient the heat will flow inwards

Explanation:

As we know that heat flux is given by the formula

q^n = K\frac{dT}{dx}

here we know that

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now we know that

q^n = 11 W/m^2

also we know that

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now we have

11 = 1.7 \frac{dT}{dx}

so temperature gradient is given as

\frac{dT}{dx} = \frac{11}{1.7} = 6.47 K/m

also in other unit it will be same

\frac{dT}{dx} = 6.47 ^oC/m

Also as we can see the equation that heat flux directly depends on the temperature gradient so more is the temperature gradient then more will be the heat flux.

For positive temperature gradient the heat will flow outwards while for negative temperature gradient the heat will flow inwards

5 0
3 years ago
The mass of the sun is 2*10^30 kg and its radius is
Marta_Voda [28]

Explanation:

Distance d=1.5×108 km=1.5×1011 m

Mass of the sun, m=2×1030 kg

Mass of the earth, M=6×1024 kg

Force of gravitation, F=G×d2m×M

F=6.7×10−11×(1.5×1011)22×1030×6×1024=3.57×1022 N

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Evgesh-ka [11]

Answer:

Explanation:

Magnetic field due to moving charge =

B=\frac{\mu_0}{4\pi} \times \frac{qv}{r^2}

q is charge moving with velocity v and r is distance from point at which field is calculated .

For alpha particle

B_1=\frac{\mu_0}{4\pi} \times \frac{2\times 1.6\times10^{-19}\times 2.8\times 10^5}{(8.25\times 10^{-9})^2}

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B_2=\frac{\mu_0}{4\pi} \times \frac{ 1.6\times10^{-19}\times 2.8\times 10^5}{(8.25\times 10^{-9})^2}

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Hence

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8 0
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At a construction site a pipe wrench struck the ground with a speed of 31 m/s. (a) From what height was it inadvertently dropped
max2010maxim [7]

Answer:

h = 48.05m

h = 48.05mt = 3.1 sec

Explanation:

v = 31 m/s

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t = √2h/g

t = √(2×48.05)/10

t = 3.1 sec

8 0
4 years ago
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