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maks197457 [2]
3 years ago
9

A stationary source S generates circular outgoing waves on a lake. The wave speed is 5.0 m/s and the crest-to-crest distance is

2.0 m. A person in a motorboat heads directly toward S at 3.0 m/s. To this person, the frequency of these waves is:
Physics
1 answer:
Aleonysh [2.5K]3 years ago
4 0

Answer:4 Hz

Explanation:

Speed of wave v=5 m/s

crest to crest distance \lambda =2 m

velocity of observer v_0=3 m/s

actual frequency f=\frac{velocity}{\lambda }

f=\frac{5}{2}=2.5 Hz

Apparent frequency f'=f(\frac{v+v_0}{v})

f'=2.5\times \frac{5+3}{5}

f'=4 Hz      

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\frac{N_P}{N_s} = \frac{E_p}{E_s} \\\\E_s = \frac{N_sE_p}{N_p} \\\\E_s = \frac{1875*130}{375} \\\\E_s = 650 \ V

The rms voltage (in V) measured across the secondary coil is calculated as;

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