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3 years ago

Need help please in physics

Physics

1 answer:

AnnZ [28]3 years ago

3 0

Answer:

the switching circuitry is opened the soft iron armature is replaced to tasty le macha the switching circuitry is closed explain what happens when the switch circuit is a wonder you know about the characteristics of open to close this which right take the example of an electric generator for an electric motor which rotates in half rotation and change the armature and just try it ok I am sorry

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Experimental tests have shown that hammerhead sharks can detect magnetic fields. In one such test, 100 turns of wire were wrappe

Triss [41]

B = µo*N*I/2r

So B = 4πx10^-7*150*1.6/2*3.5 = 4.31x10^-5T

7 0

3 years ago

Public television station KQED in San Francisco broadcasts a sinusoidal radio signal at a power of 777 kW. Assume that the wave

ehidna [41]

Answer:

A) P = 3.3 × 10^(-11) Pa

B) Amplitude of electric field = 1.931 N/C

Amplitude of magnetic field = 6.44 × 10^(-9) T

C) μ_av = 1.65 × 10^(-11) J/m³

D) 50% each for the electric and magnetic field

Explanation:

A) First of all let's calculate intensity.

I = P_av/A

We are given;

P_av = 777 KW = 777,000 W

Distance = 5 km = 5000 m

Thus;

I = 777000/(2π × 5000²)

I = 0.00495 W/m²

Now, the average pressure would be given by the formula;

P = 2I/C

Where C is speed of light = 3 × 10^(8) m/s

P = (2 × 0.00495)/(3 × 10^(8))

P = 3.3 × 10^(-11) Pa

B) Formula for the amplitude of the electric field is gotten from;

E_max = √[2I/(εo•c)].

Where εo is the Permittivity of free space with a constant value of 8.85 × 10^(−12) c²/N.mm²

I and c remain as before.

Thus;

E_max = √[(2 × 0.00495)/(8.85 × 10^(−12) × 3 × 10^(8))]

E_max = √3.72881355932

E_max = 1.931 N/C

Formula for amplitude of magnetic field is gotten from;

B_max = E_max/c

B_max = 1.931/(3 × 10^(8))

B_max = 6.44 × 10^(-9) T

C) Formula for average density is;

μ_av = εo(E_rms)²

Now, E_rms = E_max/√2

Thus;

E_rms = 1.931/√2

μ_av = 8.85 × 10^(−12) × (1.931/√2)²

μ_av = 1.65 × 10^(-11) J/m³

D) The energy density for the electric and magnetic field is the same. So both of them will have 50% of the energy density.

4 0

3 years ago

I REALLY NEED HELP PLEASE

iogann1982 [59]

The correct answer is C

6 0

4 years ago

Problem 10.32

Mashcka [7]

Answer : $\alpha = -240\ rad/s^{2}$ south

Explanation :

Given that,

Force = 200 N

Length = 2.00 m

Mass = 5.00 kg

We know that , the formula of the angular acceleration

$\alpha = \dfrac{\tau}{I}\ rad/s^{2}$

We know the moment of inertia of rod

$I = \dfrac{ML^{2}}{12}$

Now, the torque is

$\tau = F\times r$

The angular acceleration

$\alpha = \dfrac{F\times r\times12}{ML^{2}}$

$\alpha = \dfrac{((200\ N\times-1\ m) + (-200\ N)\times(1\ m))\times12}{5\ kg\times2\ m\times2\ m}$

$\alpha = \dfrac{-400Nm\times12}{5kg\times4m^{2}}$

$\alpha = -240\ rad/s^{2}$

Negative sign represent of south direction.

Hence, this is the required solution.

7 0

3 years ago

Read 2 more answers

A 20-car train standing on the siding is started in motion by the train’s engine. 2 cm slack is between each of the cars, which

My name is Ann [436]

Answer:

1.81 s

Explanation:

From the given information:

The links between the cars are:

1-2, 2-3, 3-4, 4-5, 5-6, 6-7, 7-8, 8-9, 9-10, 10-11, 11-12, 12-13, 13-14, 14-15, 15-16, 16-17, 17-18, 18-19, 19-20.

where;

1 denotes the first car that joins strongly attached to the engine.

There are 19 links from the above connections and each one of them has a 2 cm slack.

Thus; the total slack = 2 × 19 = 38 cm

However, the speed of the train = 21 cm/s

Then, the time taken by the pulse to travel the length of the train is expressed by using the formula:

= length / speed

= 38 / 21

= 1.81 seconds

Thus, the required time = 1.81 s

6 0

3 years ago

Need help please in physics ​

Need help please in physics