Answer:
Yes
Explanation:
Standard temperature and pressure conditions are defined as 1 atm pressure and 273.15 K. On the other hand, standard ambient temperature and pressure conditions are defined as 1 atm pressure and 298.15 K.
Notice, however, that the only change between them is in temperature.
In any standard conditions, the standard atmospheric pressure is equal to 1 atm.
At sea level, the atmospheric pressure is also equal to 1 atm.
Therefore, we may conclude that the standard atmospheric pressure is equivalent to the normal air pressure at sea level. With an increase in altitude, however, the atmospheric pressure decreases.
Answer:
λ = 4.59 ×10⁻³ nm
Explanation:
Given data:
Energy of light = 4.33 ×10⁻¹⁴ J
Wavelength of light = ?
h = 6.626×10⁻³⁴ js
c = 3×10⁸ m/s
Solution:
Formula:
E = hc/λ
4.33 ×10⁻¹⁴ J = 6.626×10⁻³⁴ Js× 3×10⁸ m/s / λ
λ = 6.626×10⁻³⁴ Js× 3×10⁸ m/s / 4.33 ×10⁻¹⁴ J
λ = 19.878 ×10⁻²⁶ Jm / 4.33 ×10⁻¹⁴ J
λ = 4.59 ×10⁻¹² m
λ = 4.59 ×10⁻³ nm
Explanation:
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Answer:
When we kick the ball, the force we apply to it causes it to accelerate from a speed of 0 to a speed of dozens of kilometers per hour. When the ball is released from the foot, it begins to decelerate (negative acceleration) due to the force of friction that is exerted upon it (as we observed in the previous example).
Explanation:
