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4 years ago

Specific Heat of an object

Chemistry

1 answer:

Viktor [21]4 years ago

4 0

Answer:

the heat is probably alot.

Explanation:

i might be wrong i'm not sure

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The rate of gas diffusion is ---Select--- proportional to temperature because a higher temperature means a/an increase in the ki

frozen [14]

Answer:

The rate of gas diffusion is directly proportional to temperature

Explanation:

The rate of gas diffusion is

a) directly proportional to square root of temperature

b) inversely proportional to the square root of density

c) directly proportional to pressure

d) inversely proportional time and square root of molecular mass

Thus, option A is correct

8 0

3 years ago

Which list below contains only renewable resources

gulaghasi [49]

- Tidal Energy

- Biomass Energy

- Solar Energy

- Wind Energy

- Hydropower

-Ocean Thermal Energy

- Biogas

-Geothermal Energy

-Air

-water

-wood

Explanation:

renewable resources are the natural resources which will help to replace the portion got deplete. These resources will fill up the gaps by any recurring processes or any natural process in a finite time.

Most of the renewable resources are part of the earth’s ecosphere and considered as part of the earth's natural environment.

water is technically a renewable resource because it can use over and over but the sustainability of this renewable resource is a question.

5 0

3 years ago

What would be the resulting molarity of a solution made by dissolving 21.9 grams of KCl in enough water to make an 869-millilite

viktelen [127]

Molar mass KCl = <span>74.5513 g/mol

Number of moles:

21.9 / 74.5513 => 0.293 moles

Volume = 869 mL / 1000 => 0.869 L

Molarity = moles / Volume

Molarity = 0.293 / 0.869

=> 0.337 M</span>

8 0

4 years ago

What is the standard entropy change for the reaction below? 2 CO(g) + 2 NO(g) → N2(g) + 2 CO2(g) S o (CO(g)) = 197.7 J/(mol·K) S

photoshop1234 [79]

Answer:

$\Delta _RS^o=-230J/(mol*K)$

Explanation:

Hello,

In this case, for the given chemical reaction:

$2 CO(g) + 2 NO(g) \rightarrow N_2(g) + 2 CO_2(g)$

The standard entropy change is computed by subtracting the products standard enthalpy and the reactants standard enthalpy considering each species stoichiometric coefficients:

$\Delta _RS^o=S ^o_{N2(g)}+2S ^o_{CO2(g)}-2S ^o_{CO(g)}-2S ^o_{NO(g)}\\\\\Delta _RS^o=191.6J/(mol*K)+2*213.8J/(mol*K) -2*213.8J/(mol*K) -2*210.8J/(mol*K)\\\\\Delta _RS^o=-230J/(mol*K)$