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horrorfan [7]
3 years ago
14

Shuffle a deck of cards and turn over the first card. What is the sample space of the experiment? How many outcomes are in the e

vent that the first card is a heart?
Physics
1 answer:
True [87]3 years ago
5 0

Answer:

The sample space contain 52 entities as shown in explanation.

The event that first card is a heart, contains 13 outcomes as shown in the explanation.

Explanation:

The sample space will contain 52 entities as follows:

Sample Space = {Heart 1, Heart 2,Heart 3,Heart 4,Heart 5,Heart 6,Heart 7,Heart 8,Heart 9,Heart Jack,Heart Queen, Heart King,Heart A,Spade 1, Spade 2,Spade 3,Spade 4,Spade 5,Spade 6,Spade 7,Spade 8,Spade 9,Spade Jack,Spade Queen, Spade King,Spade A, Diamond 1, Diamond 2,Diamond 3,Diamond 4,Diamond 5,Diamond 6,Diamond 7,Diamond 8,Diamond 9,Diamond Jack,Diamond Queen, Diamond King,Diamond A, Club 1, Club 2,Club 3,Club 4,Club 5,Club 6,Club 7,Club 8,Club 9,Club Jack,Club Queen, Club King,Club A}

There will be 13 outcomes in the event that first card is a heart, as follows:

Event(first card hearts) = {Heart 1, Heart 2,Heart 3,Heart 4,Heart 5,Heart 6,Heart 7,Heart 8,Heart 9,Heart Jack,Heart Queen, Heart King,Heart A}

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Which statements below are true?
Ilya [14]

The correct statements are that the speed decreases as the distance decreases and speed increases as the distance increases for the same time.

Answer:

Option A and Option B.

Explanation:

Speed is defined as the ratio of distance covered to the time taken to cover that distance. So Speed = Distance/Time. In other words, we can also state that speed is directly proportional to the distance for a constant time. Thus, the speed will be decreasing as there is decrease in distance for the same time. As well as there will be increase in speed as the distance increases for the same time. So option A and option B are the true options. So if there is decrease in the distance due to direct proportionality the speed will also be decreasing. Similarly, if the distance increases, the speed will also be increasing.

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3 years ago
Although these quantities vary from one type of cell to another, a cell can be 1.9 μm in diameter with a cell wall 60 nm thick.
DaniilM [7]

Answer: 2(10)^{-9} mg

Explanation:

We know the total diameter of the cell (assumed spherical) is:

d=1.9\mu m=1.9(10)^{-6} m

Then its total radius r=\frac{d}{2}=\frac{1.9(10)^{-6} m}{2}=9.5(10)^{-7} m

On the other hand, we know the thickness of the cell wall is r_{t}=60 nm= 60(10)^{-9} m and its density is the same as water (\rho=997 kg/m^{3}).

Since density is the relation between the mass m and the volume V:

\rho=\frac{m}{V}

The mass is: m=\rho V (1)

Now if we are talking about this cell as a thin spherical shell, its volume will be:

V=\frac{4}{3}\pi R^{3} (2)

Where  R=r-r_{w}=9.5(10)^{-7} m - 60(10)^{-9} m

Then:

V=\frac{4}{3}\pi (9.5(10)^{-7} m - 60(10)^{-9} m)^{3} (3)

V=2.952(10)^{-18} m^{3} (4)

Substituting (4) in (1):

m=(997 kg/m^{3})(2.952(10)^{-18} m^{3}) (5)

m=2.94(10)^{-15} kg (6)

Knowing 1 kg=1000 g and 1 mg=0.001 g:

m=2.94(10)^{-15} kg=2(10)^{-9} mg

7 0
3 years ago
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