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horrorfan [7]
3 years ago
14

Shuffle a deck of cards and turn over the first card. What is the sample space of the experiment? How many outcomes are in the e

vent that the first card is a heart?
Physics
1 answer:
True [87]3 years ago
5 0

Answer:

The sample space contain 52 entities as shown in explanation.

The event that first card is a heart, contains 13 outcomes as shown in the explanation.

Explanation:

The sample space will contain 52 entities as follows:

Sample Space = {Heart 1, Heart 2,Heart 3,Heart 4,Heart 5,Heart 6,Heart 7,Heart 8,Heart 9,Heart Jack,Heart Queen, Heart King,Heart A,Spade 1, Spade 2,Spade 3,Spade 4,Spade 5,Spade 6,Spade 7,Spade 8,Spade 9,Spade Jack,Spade Queen, Spade King,Spade A, Diamond 1, Diamond 2,Diamond 3,Diamond 4,Diamond 5,Diamond 6,Diamond 7,Diamond 8,Diamond 9,Diamond Jack,Diamond Queen, Diamond King,Diamond A, Club 1, Club 2,Club 3,Club 4,Club 5,Club 6,Club 7,Club 8,Club 9,Club Jack,Club Queen, Club King,Club A}

There will be 13 outcomes in the event that first card is a heart, as follows:

Event(first card hearts) = {Heart 1, Heart 2,Heart 3,Heart 4,Heart 5,Heart 6,Heart 7,Heart 8,Heart 9,Heart Jack,Heart Queen, Heart King,Heart A}

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Answer:

10 km

Explanation:

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8 0
1 year ago
EX 6-1 A ball is twirled on a 0.870 - m-long string with a constant speed of 3.36 m / s . Calculate the acceleration of the ball
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Answer:

a=12.97\ m/s^2

Explanation:

Given that,

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We need to find the acceleration of the ball. The acceleration acting on the ball is centripetal acceleration. It is given by :

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3 years ago
What happens to the electrostatic force between two charged particles if the distance between them is doubled?
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The Hubble Space Telescope orbits the Earth at approximately 612,000m altitude. Its mass is 11,100 kg and the mass of earth is 5
nexus9112 [7]

Answer:

7.55 km/s

Explanation:

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G\frac{mM}{R^2}=m\frac{v^2}{R}

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v = ? is the orbital velocity of the Hubble telescope

Re-arranging the equation and substituting numbers, we find the orbital velocity:

v=\sqrt{\frac{GM}{R}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24} kg)}{6.99\cdot 10^6 m}}=7548 m/s=7.55 km/s

6 0
3 years ago
QUESTION 9
Alik [6]

Answer:

The answer is option a.

Hope this helps

4 0
3 years ago
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