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Liono4ka [1.6K]
3 years ago
7

Using your model, create the following scenarios. i. Night time, the Americas. <-- what would this look like?

Physics
1 answer:
vodomira [7]3 years ago
3 0

Answer:

I night time, the Sun will be on the opposite side of the planet that is in the night time, and the Mon will be in different positions (depending on the hour)  in the same side that the place that is in the night time.

Then in the model, if you left the Earth unchanged, you need to place the Sun bellow the Earth (So America is in the opposite side) And the moon above the Earth (So in America a person can see the moon)

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PLEASE HELP!
lana66690 [7]

Answer:

x = 4.32 [m]

Explanation:

We must divide this problem into three parts, in the first part we must use Newton's second law which tells us that the force is equal to the product of mass by acceleration.

∑F = m*a

where:

F = force = 700 [N]

m = mass = 2030 [kg]

a = acceleration [m/s²]

Now replacing:

F=m*a\\700=2030*a\\a = 0.344[m/s^{2}]

Then we can determine the final speed using the principle of conservation of momentum and amount of movement.

(m_{1}*v_{1})+Imp_{1-2}=(m_{1}*v_{2})

where:

m₁ = mass of the car = 2030 [kg]

v₁ = velocity at the initial moment = 0 (the car starts from rest)

Imp₁₋₂ = The impulse or momentum (force by the time)

v₂ = final velocity after the impulse [m/s]

(2030*0) + (700*5)=(2030*v_{2})\\3500 = 2030*v_{2}\\v_{2}=1.72[m/s]

Now using the following equation of kinematics, we can determine the distance traveled.

v_{2}^{2} =v_{1}^{2}+2*a*x

where:

v₂ = final velocity = 1.72 [m/s]

v₁ = initial velocity = 0

a = acceleration = 0.344 [m/s²]

x = distance [m]

1.72^{2}=0^{2} +(2*0.344*x) \\2.97 = 0.688*x\\x = 4.32 [m]

8 0
3 years ago
A car starts from rest and moves along the positive x-axis with a constant acceleration of 5 m/s/s for 8 seconds. It then contin
tino4ka555 [31]

Answer:

340

Explanation:

Because you are moving at 5 m/s^2 for 8 seconds, you need to do some arithmetic to get the distance covered in the beginning. TO do this, you do 5 + 5*2 + 5*3 + 5*4 + 5*5 + 5*6 + 5*7 + 5*8, and once you have passed eight seconds, you need 4 more seconds with constant velocity, or 4(5*8). Your final equation would be 5+10+15+20+25+30+35+40+40+40+40+40. Hope this helps!

5 0
3 years ago
Read 2 more answers
When cooking frozen cheese ravioli, the directions say to put the 255 grams of filled pasta into 3 quarts of boiling water. Why
nadya68 [22]

Answer:

a. T_f=95.14^{\circ}C

b. T_f=86.4^{\circ}C

It is asked for 3 quarts of water  because it prevents the temperature drop.

Explanation:

Given:

  • mass of frozen cheese, m_c=255\ g
  • quantity of water suggested for the given cheese, m_w=3\ quarts\times 946.35=2839.05\ g
  • initial temperature of cheese, T_{ic}=-40^{\circ}\ C
  • specific heat of cheese, c_c=0.4\ cal.g^{-1}.^{\circ}C^{-1}
  • initial temperature of water, T_{iw}=100^{\circ}\ C

a.

  • we have specific heat of water, c_w=1\ cal.g^{-1}.^{\circ}C^{-1}

so now, we use the heat equation to find the amount of heat exchange during the process:

m_c\times c_c\times \Delta T=m_w\times c_w\times \Delta T

255\times 0.4\times (T_f-(-40))=2839.05\times 1\times (100-T_f)

T_f=95.14^{\circ}C

b.

when using 1 quart of water:

255\times 0.4\times (T_f-(-40))=946.35\times 1\times (100-T_f)

T_f=86.4^{\circ}C

It is asked for 3 quarts of water  because it prevents the temperature drop.

3 0
3 years ago
Light travels at a speed of 3.00 x 10^11 cm/s. What is the speed of light in kilometers/hour?
rewona [7]

As 1 km = 1000 m = 1000,00 cm,

So, 1 cm = (1/1000,00) km

1 hour = 60 × 60 s = 3600 s

So,  1 s = (1 / 3600) hour

The light travels at a speed of 3.00 \times 10^{11}  \ cm/s.

In kilometer/hour,

3.00 \times 10^{11}  \ cm/s = 3.00 \times 10^{11} \frac{(1/1000,00) km}{ (1 / 3600) hour} = 108 \times 10^8 \ km/hour


4 0
4 years ago
What is temperature? Question 10 options:
vfiekz [6]
A. An indirect measure of heat energy
7 0
3 years ago
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