Question

Calculate the terminal velocity of a rain drop of radius 0.12cm​

Answer 1

Explanation:

Given that,

The radius of rain drop, r = 0.12 cm = 0.0012 m

The viscocity of air is, $\eta=18\times 10^{-5}\ poise$

Let the viscous force is, $F = 0.010173\ N$

The viscous force is given by :

$F=6\pi \eta rv\\\\v=\dfrac{F}{6\pi \eta r}$

Put all the values,

$v=\dfrac{0.010173}{6\pi 18\times 10^{-5}\times 0.0012 }\\\\v=2498.58\ m/s$