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3 years ago

What is the quotient for the equation above?

Mathematics

2 answers:

Vladimir [108]3 years ago

8 0

Answer:

The correct answer is 32.5

____ [38]3 years ago

4 0

ANSWER: 32.5 I got you homie

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HELP PLS <3 ASAP <br> KSKXNXNNmxmx

nydimaria [60]

Answer:

sbshsbsbhshsndjdudbdjdjdjdb

Step-by-step explanation:

shsbshshudhdbdudjdjdsbsbsb

6 0

3 years ago

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c} {6}\\ {11} \end{array}\right]}$

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0

3 years ago

Help 5y^5/y^3 a) 5y^2 b) 5/y^2 c) 5y^8 d) 5y

WARRIOR [948]

Answer:

a) 5y²

Step-by-step explanation:

5 divided by 1 is still 5

y^5/y^3 subtract the exponents since the base is the same

6 0

3 years ago

Read 2 more answers

4y+3y simplify

kykrilka [37]

Answer:

<h2>✓ Simplifying Expressions</h2>

$4y + 3y$

<h3>Solution:</h3>

$4y + 3y \\ = 7y$

Adding the numerical coefficient with the terms that have the same variables. Meaning they are like terms. Adding the base and then copy the variables.

<h3>> Therefore, the answer is 7y.</h3>

4 0

3 years ago

Read 2 more answers

Suppose you choose a marble from a bag containing 3 red marbles, 5 white marbles, and 4 blue marbles. You return the first marbl

Veseljchak [2.6K]

Answer:

P(red and blue) = 0.1667

Step-by-step explanation:

Let A represent choosing a red marble, there are 3 red marbles

Let B represent choosing a blue marble, there are 4 blue marbles

There are 12 total marbles

Then...

P(A) = 3/12

P(B) = 4/12

choosing the first one, then replacing means the first choice has no effect on the probabilities of the second choice, so the situation is independent.

When calculating the probability of independent events, you multiply the probabilities together. There are 2 scenarios where we can get a red and blue marble..

Choosing a red, then a blue marble, the probability is

(3/12)( 4/12) = 12/144 = 1/12

Choosing a blue, then a red marble, the probability is

(4/12)(3/12) = 12/144 = 1/12

So we have a

(1/12) + (1/12) = 2/12 = 1/6 chance for that to happen, to

P(A and B) = 1/6 = 0.1667

6 0

3 years ago