V=LWH=20
L is 5 more than W
V=5+W
H is 1 less than W
H=-1+W
easy, sub 5+W for L and -1+W for H in LWH=V=20
20=(5+W)(W)(-1+W)
expand
20=W^3+4W^2-5W
minus 20 both sides
W^3+4W^2-5W-20=0
either factor or graph to find the possible values for W
(W+4)(W^2-5)=0
set each to zero
W+4=0
W=-4
impossible, measures cannot be negative
W^2-5=0
add 5
W^2=5
sqrt both sides
W=√5
sub back
L=5+W
L=5+√5
aprox
7.24 rounded
H=-1+W
H=-1+√5
aprox
1.24 rounded
the dimentions are
√5 by (5+√5) by (-1+√5) or aprox
2.24in by 7.24in by 1.24in
True because it is used to collect information on data tables and other things.
Answer:
The answer is 2
Step-by-step explanation:
Multiply the numerator and denominator by the conjugate.
Answer:
Step-by-step explanation:
When you have four terms and 3rd degree equation (the highest power is 3) you will want to try to "factor by grouping"
Group together two terms, watch out for the negative signs!
x^3 + 2x^2-5x-10=0
(x^3 + 2x^2) - (5x+10)=0
Find a common factor in each group and factor it out. You're hoping that what is left in the parenthesis is the same in both cases.
x^2(x+2)-5(x+2)=0
Now you can factor out that (x+2) because it is both terms.
x^2(x + 2) - 5(x + 2)=0
~~~~ ~~~~
Pull these out.
What will be left is the x^2 and the - 5 (dont lose that - in front of the 5)
(x + 2)(x^2 - 5) = 0
If all you have to do is factor, then you're done. It is factored. But if you have to "solve" also, then put x+2=0 and x^2-5=0 and solve.
x = -2 and x = +- sqrt5
The other person their trying to get your ip
