Question

You are given a sample of metal and asked to determine its specific heat. You weigh the sample and find that its weight is 27.2 N . You carefully add 1.45×104 J of heat energy to the sample and find that its temperature rises 16.0 ∘C

Answer 1

Answer:

c=326.5177 J/kg.K

Specific heat is c=326.5177 J/kg.K

Explanation:

In order ti find the specific heat, we will proceed as follow:

Formula we are going to use is:

$Q=m*c*\Delta T$

Where:

Q is the heat energy added

m is the mass of sample

c is the specific heat

$\Delta T$ is the temperature Rise.

First we will find the mass:

Weight=m*g  (g is gravitational acceleration=9.8 m/s^2)

$m=\frac{weight}{g} \\m=\frac{27.2}{9.8} \\m=2.7755 \ kg$

Rearranging above formula:

$c=\frac{Q}{m* \Delta T}$

$c=\frac{1.45*10^4}{2.7755*16}$

c=326.5177 J/kg.K

Specific heat is c=326.5177 J/kg.K