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RideAnS [48]
3 years ago
7

An imaginary dense star z has 1/5 the radius of earth, but 1000 times the earths. how much would a mass weighing 1.0n on earth w

eigh on star z
Physics
1 answer:
andrew11 [14]3 years ago
8 0
A 1-newton mass on earth would be 1000 newtons on star Z.

Funny enough, stars like this exist~! They're called "Neutron Stars."
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The weight of a cuboid box is 288 N. Find its mass.​
zalisa [80]

Answer:

29.39 kg

Explanation:

From the question,

W = mg...................... Equation 1

Where W = weight of the cuboid box, m = mass of the cuboid box, g = acceleration due to gravity.

make m the subject of the equation

m = W/g.................. Equation 2

Given: W = 288 N

Constant: g = 9.8 m/s²

Substitute these values into equation 2

m = 288/9.8

m = 29.39 kg

4 0
3 years ago
A room has a heater on one side and
Serjik [45]

Answer:

the warm air would be up and cool would be down

Explanation:

warm air is less dense and cool air is more dense

5 0
2 years ago
In which of these biomes do nutrients cycle fastest?
nordsb [41]

Answer:

the answer is tropical rainfores

7 0
3 years ago
A 72-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.
Shalnov [3]

Answer:

Explanation:

During the first .8 s , the elevator is under acceleration . It starts from initial velocity u = 0 , final velocity v = 1.2 m /s , time = .8 s

v = u + at

1.2 = 0 +  .8 a

a = 1.2 / .8

= 1.5 m /s²

During the acceleration in upward direction , let reaction force of ground on man be R .

Net force on man = R - mg

Applying Newton's 2 nd law

R - mg = ma

R = m ( g + a )

= 72 ( 9.8 + 1.5 )

= 813.6 N .

This reaction force will be measured by spring scale , so reading of spring scale will be 813.6 N .

3 0
3 years ago
The tallest building in the world, according to some architectural standards, is the Taipei 101 in Taiwan, at a height of 1671 f
Andrej [43]

Answer:

35.14°C

Explanation:

The equation for linear thermal expansion is \Delta L = \alpha L_0\Delta T, which means that a bar of length L_0 with a thermal expansion coefficient \alpha under a temperature variation \Delta T will experiment a length variation \Delta L.

We have then \Delta L = 0.481 foot, L_0 = 1671 feet and \alpha = 0.000013 per centigrade degree (this is just the linear thermal expansion of steel that you must find in a table), which means from the equation for linear thermal expansion that we have a \Delta T =\frac{\Delta L }{\alpha L_0} = 22.14°. As said before, these degrees are centigrades (Celsius or Kelvin, it does not matter since it is only a variation), and the foot units cancel on the equation, showing no further conversion was needed.

Since our temperature on a cool spring day was 13.0°C, our new temperature must be T_f=T_0+\Delta T = 35.14°C

3 0
4 years ago
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