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Blababa [14]
3 years ago
12

I need help with unscrambling letters for the answers I got b a l q u o p o f I don't need the answers already I just need help

unscrambling them from the letter Bank the leftover letters are n t g i s r e e t. g some one please help​
Mathematics
1 answer:
spayn [35]3 years ago
3 0

Answer:

it may be registered or register, or registering. i am not entirely sure.

Step-by-step explanation:

You might be interested in
What's 2.5 divided by 5
USPshnik [31]
Your answer would be 0.5 ;) Hope this helps
3 0
2 years ago
Draw a number line -5 through 5 and mark 2x<6
inna [77]

Answer:

x < 3

Step-by-step explanation:

Before number line can be drawn, there is need to find the value of x in the inequality given. Thus,

2x < 6

Divide both sides by 2

\frac{2x}{2}  <  \frac{6}{2}

x < 3

The number line is indicated in the attached picture.

8 0
3 years ago
Solve this equation:<br><br> |x-2|=6x+18
sineoko [7]
X-2=6x+18
-x -x
-2=5x+18
-18 -18
-20=5x
x=-4
5 0
2 years ago
The average of 5 quiz grades is 10. When the lowest grade is dropped and the new average is calculated, it turns out to be 11. W
V125BC [204]

Answer:

The score of the dropped grade is 6

Step-by-step explanation:

To find the average of a set of numbers you need to add all the numbers and divide by how many numbers there are. The problem wants you to solve it in reverse. Let put this into an algebraic equation with a, b, c, d, and e being the variables of the test scores

(a+b+c+d+e)/5=10

Then we can multiply both sides by 5 and get

a+b+c+d+e=50

Lets assume that c is the lowest test score. To calculate the average of that we get

a+b+d+e/4=11

Doing the same thing, we know that a+b+d+e=44

Now compare the two:

a+b+c+d+e=50

a+b+d+e=44

We can now know that c=50-44=6

So, 6 is the score of the dropped quiz. Hope that helped!

4 0
2 years ago
The pointer of the vibration measuring instrument is observed to move between the 0.1 and0.3 marks on the vertical scale, when s
Norma-Jean [14]

Answer:

Step-by-step explanation:

Given points moves b/w 0.1 of 0.3 marks Hence amplitude is 0.2

Also , frequency (w) = 100 rad/s.

Natural frequency (wn) = √K/m

K = 20 N/mm x 1000mm/1m = 20000N/M

W = 1000mm/1m = 20,000N/M

FormulaX = FolK/1 - (w/wn)²

0.2 = b/20000/1 - (100/50)²

Given forcing frequency was doubled, W1 = 2 x 100=200rad/s

X1 =b/20,000/1 - (200/20)²

0.2/11 = 1 - (200/50)²/1 - (100/50)² = 0.2/11 = -15^5– 3

X1 = 0.04

8 0
3 years ago
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