Answer:
10.5 in
Step-by-step explanation:
Given
Required
Find length AC
The question is not detailed enough; so, I'll assume that b represents line AC.
Having said that;
We start by multiplying both sides by b
Divide both sides by tan(55)
Find tan(55)
<em>(Approximated)</em>
<em />
Length AC is 10.5
a) The halfway number is .
b) The ascending order is ,
and
.
<u>Step-by-step explanation:</u>
a)Halfway number is otherwise Middle number.
The halfway number of two numbers = .
The halfway for and
=
.
=.
= .
=.
∴Halfway =.
=
The halfway for and
=
.
b) The ascending order is ,
and
.
Pictures always help; see the one I've attached for reference.
Call the first vector (from HQ to the supply drop) u and the second vector (from supply drop to medics) v. We then want to find w, the vector from the medics to HQ, which corresponds to the vector -(u + v). (This is because u + v is the vector pointing from HQ to the medics; we're talking about the one in the opposite direction.)
Write the vectors in horizontal/vertical component form:
u = (125 km) (cos 235º x + sin 235º y) = (-71.70 x - 102.39 y) km
v = (75 km) (cos 110º x + sin 110º y) = (-25.65 x + 70.48 y) km
Why these angles?
Add the vectors:
u + v = (-97.35 x - 31.92 y) km
Multiply by -1 to get the vector w:
w = -(u + v) = (97.35 x + 31.92 y) km
The distance covered by this vector is equal to its magnitude:
||w|| = √((97.35 km)^2 + (31.92 km)^2) = 102.45 km
The direction <em>θ</em> is given by
tan<em>θ</em> = (31.92 km)/(97.35 km) ==> <em>θ</em> = 18.15º
