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2 years ago

Which equation represents a line that has a slope of 7 and passes through the point of (2,6)?

Mathematics

2 answers:

borishaifa [10]2 years ago

8 0

Answer:

y-6 = 7(x-2) point slope form

y = 7x-8 slope intercept form

Step-by-step explanation:

Since we know a point and a slope, we can use point slope form

y-y1 = m(x-x1)

y-6 = 7(x-2)

This is point slope form of the equation

If we want it in slope intercept form

Distribute the 7

y-6 = 7x-14

Add 6 to each side

y-6+6 = 7x-14+6

y = 7x-8

Strike441 [17]2 years ago

7 0

Answer:

y=7x -8

Step-by-step explanation:

I used desmos but you can also use an equation. I'm sure you're teacher taught you how.

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If JK and LM are congruent and parallel, then JKL and MLK are congruent.

viktelen [127]

Answer:

Given statement is TRUE.

Step-by-step explanation:

Given that line segment JK and LM are parallel. From picture we see that LK is transversal line.

We know that corresponding angles formed by transversal line are congruent.

Hence ∠JKL = ∠ MLK ...(i)

Now consider triangles JKL and MLK

JK = LM {Given}

∠JKL = ∠ MLK { Using (i) }

KL = KL {common sides}

Hence by SAS property of congruency of triangles, ΔJKL and ΔMLK are congruent.

Hence given statement is TRUE.

3 0

3 years ago

Which of the following is the standard form of the equation 5x2 - 20x = 15?

Finger [1]

x= +7 or x=2-7 let me know if you need an explanation <3

5 0

2 years ago

Rewrite each fraction in simplest form using the GCF of the numerator and denominator.

Elanso [62]

Answer:

$\sf 6. \quad \dfrac{7}{10}$

$\sf 7. \quad \dfrac{5}{17}$

Step-by-step explanation:

<h3><u>Question 6</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

42 = 2 × 3 × 7
60 = 2 × 2 × 3 × 5

42 and 60 share one 2 and one 3 in common.

Multiply them together to get the GCF: 2 × 3 = 6.

Therefore, 6 is the GCF of 42 and 60.

Divide the numerator and the denominator by the found GCF:

$\implies \sf \dfrac{42 \div 6}{60 \div 6}=\dfrac{7}{10}$

<h3><u>Question 7</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

80 = 2 × 2 × 2 × 2 × 5
272 = 2 × 2 × 2 × 2 × 17

80 and 272 share four 2s in common.

Multiply them together to get the GCF: 2 × 2 × 2 × 2 = 16.

Therefore, 16 is the GCF of 80 and 272.

Divide the numerator and the denominator by the found GCF:

$\implies \sf \dfrac{80 \div 16}{272 \div 16}=\dfrac{5}{17}$

5 0

1 year ago

Read 2 more answers

There was no actually pyramid for these questions it tells you the measurements in the problem though. please help me

Nimfa-mama [501]

V=448 in^3
l=8 in
w=12
h=?
V=l•w•h/3
448=8•12•h/3 multiply both sides by 3
3•448=96•h
1344=96•h
h=1344/96
h=14 in

V=l•w•h/3
h=4in
l=3in
w=2.5 in
V=?
V=4•3•2.5/3
V=30/3
V=10 in^3

3 0

3 years ago

In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion

lys-0071 [83]

$\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$

$\displaystyle
(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\
n=5\\
k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10$

----------------------------------------------------

$\displaystyle
(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\
n=5\\
k=4\\\\
\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90$

<u>It's 90</u>

6 0

3 years ago