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SVEN [57.7K]
2 years ago
11

Find (4.54×10^8)-(3.98×10^8)

Mathematics
1 answer:
horrorfan [7]2 years ago
5 0

Answer:

5.6 *10^7

Step-by-step explanation:

Given

(4.54*10^8)-(3.98*10^8)

Required

Solve

(4.54*10^8)-(3.98*10^8)

Apply distributive law of algebra

(4.54 - 3.98) *10^8

Evaluate the expression in bracket

(0.56) *10^8

Remove bracket

0.56 *10^8

When a number is in standard form: a * 10^n

The value of a must be: 1 \le a \le 10

So, the expression becomes:

5.6 *10^{-1}*10^8

Apply law of indices

5.6 *10^{-1+8}

5.6 *10^7

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The measure of arc LM is °. The measure of angle MBL is °. The measure of angle MNL is °.
Vedmedyk [2.9K]

The measure of arc LM is 116

The measure angle MBL is 58

The measure of angle MNL is 64

5 0
3 years ago
Read 2 more answers
You buy a container of cat litter for $11.50 and a bag of cat food for x dollars. The total purchase is $16.80, which includes 5
NARA [144]

Answer:

4.46  

Step-by-step explanation:

(11.5 + x) + 5% = 16.8

11.5 + x = 16.8 - 5%

x = (16.8 - 5% ) - 11.5

x = 15.96 - 11.5

x = 4.46  

5 0
2 years ago
Read 2 more answers
Help me out guys!!!!!!!​
Dmitrij [34]

Answer:

\frac{5 \sqrt{11} }{11}

you are correct !!

3 0
2 years ago
If the inspection division of a county weights and measures department wants to estimate the mean amount of
Amanda [17]

If inspection department wants to estimate the mean amount with 95% confidence level with standard deviation 0.05 then it needed a sample size of 97.

Given 95% confidence level, standard deviation=0.05.

We know that margin of error is the range of values below and above the sample statistic in a confidence interval.

We assume that the values follow normal distribution. Normal distribution is a probability that is symmetric about the mean showing the data  near the mean are more frequent in occurence than data far from mean.

We know that margin of error for a confidence interval is given by:

Me=z/2* ST/\sqrt{N}

α=1-0.95=0.05

α/2=0.025

z with α/2=1.96 (using normal distribution table)

Solving for n using formula of margin of error.

n=(z/2ST/Me)^{2}

n=(1.96*0.05)^{2} /(0.01)^{2}

=96.4

By rounding off we will get 97.

Hence the sample size required will be 97.

Learn more about standard deviation at brainly.com/question/475676

#SPJ4

The given question is incomplete and the full question is as under:

If the inspection division of a county weights and measures department wants to estimate the mean amount of soft drink fill in 2 liters bottles to within (0.01 liter with 95% confidence and also assumes that standard deviation is 0.05 liter. What is the sample size needed?

7 0
2 years ago
Pls help I will mark brainliest
attashe74 [19]

Answer:

1066 ft^2

Step-by-step explanation:

The area of a triangle is given by the formula: 1/2bh, where b is the length of the base, and h is the height of the triangle. You are given the length of the base as 82ft. The height (more commonly referred to as the altitude) is given as 26ft. Multiply the two together and then half the result to get 1,066ft^2.

3 0
3 years ago
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