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The solution for the problem is:
Constant speed means Fnet = 0.
Let m = mass of wood block and Θ = angle of ramp; then if µk = 0.35 …
The computation would be:
Fnet = 0 = mg (sin Θ) - (µk) (mg) (cos Θ)
mg (sin Θ) = µk (mg) (cos Θ)
µk = tan Θ
Θ = arctan(µk)
= arctan (0.35)
≈ 19.3°
The density of hematite ore is <u>4.78 g/cm³</u>.
Let the mass of the ore be m₁ , the volume of the flask <em>V</em>, total mass of water and ore M, mass of water be m₂, density of ore ρ₁ and the density of water be ρ₂.
Density of a substance is defined as the mass per unit volume.
The mass of water in the flask is given by,
Calculate the volume V₂ of the water in the flask.
Calculate the volume V₁occupied by the ore in the flask.
1 ml is equivalent to 1 cm³.
Calculate the density of the ore.
The density of the hematite ore is found to be 4.78 g/.cm³
More info is needed. if it is in a controlled circuit I would say yes. but in a non controlled environment I would say no it's a dispersement.