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3 years ago

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In which of the following statements would the impact of gravity be the least? earth is pulled toward the Sun. Humans are pulled

toward earth. The moon is pulled toward earth. The Sun is pulled toward the moon.

1 answer:

Basile [38]3 years ago

3 0

Answer:

The sun is pulled toward the moon.

Explanation:

It is the sun is pulled toward the moon because the moon doesn't have a great enough gravitational force or mass to pull the sun, so it must be some external force.

You might be interested in

. (a) How long can you play tennis on the 800 kJ (about 200 kcal) of energy in a candy bar? (b) Does this seem like a long time?

galina1969 [7]

(a). The power of the candy bar is,

$P=440\text{ W}$

The time taken to play on 800 kJ energy of the candy bar is,

$t=\frac{E}{P}$

where E is the energy.

Substituting the known values,

$\begin{gathered} t=\frac{800\times10^3}{440} \\ t=1.818\times10^3\text{ s} \\ t=1818\text{ seconds} \end{gathered}$

As 1 minute is equal to 60 seconds,

Thus,

$\begin{gathered} t=1818\text{ seconds} \\ t=\frac{1818}{60} \\ t=30.3\text{ min} \end{gathered}$

Thus, the time taken to play tennis on the 800 kJ energy is 30.3 minutes.

(b). By doing the exercise, the process of digestion of food inside our body increases. Thus, the exercise does not helps us to burn the calories. But it helps us to diggest the heavy meal like candy bar easily.

The time taken to digest the canndy bar or to utilise its energy is large because it takes a lot of time to burn small amount of food and make it digest quickly.

8 0

1 year ago

A cart is pushed ahead for 3.5 s with a force of 360 N. Determine the change in momentum of the cart.

Katyanochek1 [597]

It is 356.5 just subtracts because it’s opposite

5 0

3 years ago

Locate the polyatomic ion in the compound CaCO3 <br> Ca <br> 0 <br> CO3 <br> C

dimaraw [331]

CO₃

Explanation:

The polyatomic ion in the compound CaCO₃ is CO₃.

A polyatomic ion is an ion that is made up of more than one atom that has singular property.

They are usually called radicals.

CaCO₃ ⇒ Ca²⁺ + CO₃²⁻

CO₃²⁻ is a polyatomic ion because it is made up of more than one atom.

The CO₃²⁻ is called a carbonate group.

It is made up of:

one atom of carbon
3 atoms of oxygen
a net charge of 2-

learn more:

Polyatomic ions brainly.com/question/6786947

#learnwithBrainly

4 0

3 years ago

Read 2 more answers

Gravity does not actually "pull" objects at

Radda [10]

I believe it’s (D. Any object)

5 0

3 years ago

A block of ice(m = 14.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal for

nadezda [96]

Answer:

a) The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) The final speed of the block of ice is 9.8 meters per second.

Explanation:

a) We need to calculate the weight, normal force from the ground to the block and the pull force. By 3rd Newton's Law we know that normal force is the reaction of the weight of the block of ice on a horizontal.

The weight of the block ( $W$ ), measured in newtons, is:

$W = m\cdot g$ (1)

Where:

$m$ - Mass of the block of ice, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

If we know that $m = 14\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , the magnitudes of the weight and normal force of the block of ice are, respectively:

$N = W = (14\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$N = W = 137.298\,N$

And the pull force is:

$F_{pull} = 98\,N$

The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) Since the block of ice is on a frictionless surface and pull force is parallel to the direction of motion and uniform in time, we can apply the Impact Theorem, which states that:

$m\cdot v_{o} +\Sigma F \cdot \Delta t = m\cdot v_{f}$ (2)

Where:

$v_{o}$ , $v_{f}$ - Initial and final speeds of the block, measured in meters per second.

$\Sigma F$ - Horizontal net force, measured in newtons.

$\Delta t$ - Impact time, measured in seconds.

Now we clear the final speed in (2):

$v_{f} = v_{o}+\frac{\Sigma F\cdot \Delta t}{m}$

If we know that $v_{o} = 0\,\frac{m}{s}$ , $m = 14\,kg$ , $\Sigma F = 98\,N$ and $\Delta t = 1.40\,s$ , then final speed of the ice block is:

$v_{f} = 0\,\frac{m}{s}+\frac{(98\,N)\cdot (1.40\,s)}{14\,kg}$

$v_{f} = 9.8\,\frac{m}{s}$

The final speed of the block of ice is 9.8 meters per second.

6 0

3 years ago