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3 years ago

How does Newton's first law of motion affect people in a car crash?

1 answer:

4 0

Because gravity pictures and post the person to the force of the front or the back of the vehicle and the car has been hit from

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Two waves overlap producing a new wave that exhibits destructive

suter [353]

Answer:B

Explanation:

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3 years ago

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What is an example of a invertebrate that doesn’t have an exoskeleton?

Tatiana [17]

Invertebrate means those organism which doesnot have backbone in their body .Some of the examples are:

1.Spider

2.earthworm

3.Starfish

4.Sea urchins.

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3 years ago

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A round object of mass 10 kg and radius 0.5 m rolls without slipping down a hill from a height of 4.5 m. If its speed at the bot

Mice21 [21]

Answer:

moment of inertia is 2.72 kg m²

Explanation:

given data

mass m = 10kg

height h = 4.5 m

radius r = 0.5 m

speed v = 6.5 m/s

to find out

moment of inertia

solution

we apply here conservation of energy

that is

mgh = 1/2 ×mv² + 1/2 × Iω²

here I is moment of inertia we find and

we know ω = Velocity / radius = 6.5 / 0.5 = 13

and g = 9.8

so put here all these value

10 (9.8) 4.5 = 1/2 ×(10)(6.5)² + 1/2 × I(13)²

441 = 211.25 + 1/2 × I( 169 )

I = 2.72

so moment of inertia is 2.72 kg m²

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3 years ago

A size-5 soccer ball of diameter 22.6 cm and mass 426 g rolls up a hill without slipping, reaching a maximum height of 5.00 m ab

maria [59]

Answer:

W = 0.678 rad/s

Explanation:

Using the conservation of energy:

$E_i =E_f$

Roll up and hill without slipping is the sumatory of two energys, rotational and translational, so:

$\frac{1}{2}IW^2+ \frac{1}{2}mV^2 = mgh$

where I is the moment of inertia, W the angular velocity at the base of the hill, m the mass of the ball, V the velocity at the base of the hill, g the gravity and h the altitude.

First, we will find the moment of inertia as:

I = $\frac{2}{3}mR^2$

where m is the mass and R the radius, so:

I = $\frac{2}{3}(0.426kg)(11.3m)^2$

I = 36.26 Kg*m^2

Then, replacing values on the initial equation, we get:

$\frac{1}{2}(36.26)W^2+ \frac{1}{2}(0.426kg)V^2 = (0.426kg)(9.8)(5m)$

also we know that:

V =WR

so:

$\frac{1}{2}(36.26)W^2+ \frac{1}{2}(0.426kg)W^2R^2 = (0.426kg)(9.8)(5m)$

Finally, solving for W, we get:

$W^2(\frac{1}{2}(36.26)+ \frac{1}{2}(0.426kg)(11.3m)^2) = (0.426kg)(9.8)(5m)$

W = 0.678 rad/s

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3 years ago

Average velocity equals distance travelled divided by speed time

Ostrovityanka [42]

Answer: The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time

HOPE THIS HELPS! :)

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3 years ago

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