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Bond [772]
4 years ago
7

Which expressions are equivalent to 7 (negative three-fourths x minus 3)? Select two options.

Mathematics
2 answers:
polet [3.4K]4 years ago
7 0

<em><u>The equivalent expressions are:</u></em>

7(-\frac{3}{4}x - 3) = (7 \times \frac{-3}{4}x) + (7 \times -3)\\\\7(-\frac{3}{4}x - 3) = \frac{-21x}{4} - 21

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

7(-\frac{3}{4}x - 3)

We have to find the equivalent expressions

By distributive property,

a(b + c) = ab + ac

Therefore,

7(-\frac{3}{4}x - 3) = (7 \times \frac{-3}{4}x) + (7 \times -3)\\\\7(-\frac{3}{4}x - 3) = \frac{-21x}{4} - 21

Thus equivalent expressions are found

Elan Coil [88]4 years ago
7 0

Answer:

Im pretty sure its a and e

Step-by-step explanation:

lmk if im wrong or right

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Hope this helps! :)

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3 years ago
How would I write a function rule f(x) = _x+_ If I have an x and y chart?
san4es73 [151]
Y=ax+b. As simple as that!
3 0
3 years ago
Round 104,547 to 3 significant figures
Wittaler [7]
104,547 to 3 significant figures is just 104,500

4 0
4 years ago
Simplify:( 2x - 2)( 3x^2 + 9x - 3). What is the coefficient of the quadratic term?
mario62 [17]
You can use the distributive property and multiply this out.
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The coefficient of the x² term is 12.

_____
You can do this in your head using the techniques of Vedic mathematics. Write the coefficients of the two expressions, putting 0 for the x² coefficient in the first factor.
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  3 9 -3

The x² term of the product will be the sum of the products of terms whose degrees add to 2. That is, the first term of the first row times the last term of the second row, plus the product of the middle two numbers in each row, plus the product of the first term in the second row times the last term in the first row.

Here's a more visual representation of the products that get added to get the coefficient of the x² term.
  0 2 -2
  3 9 -3 . . . . product is 0

  0 2 -2
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  0 2 -2
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The sum, of course, is 0 +18 -6 = 12
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Answer:

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6 0
3 years ago
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