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exis [7]
3 years ago
8

Use the diagram to answer the question. What happens at night?

Physics
2 answers:
Svet_ta [14]3 years ago
8 0

Answer:

Land breeze occurs at night

Explanation:

Land breeze is usually defined as the wind that blows from the land areas to the ocean surface. It occurs during the night time. It is because the land areas have the ability to release heat at a faster rate, in comparison to the ocean water bodies. When the land areas cools, the wind carries the cold and denser prevailing air and reaches the ocean surface in order to balance the warm rising air from the oceans. This is how the heat on earth is being balanced by the simultaneous occurrence of land and sea breeze.

melamori03 [73]3 years ago
7 0
The return flow goes to the right and instead of sea breeze, there's land breeze.
You might be interested in
Se deja caer una pelota inicialmente en reposo desde una altura de 50m sobre el nivel del suelo. ¿cuanto tiempo requiere para ll
umka2103 [35]

Answer:

a) t = 3.2 s

b) v_{f} = -32 m/s

Explanation:

a) El tiempo requerido para llegar al suelo se puede calcular usando la siguiente fórmula:

t = \sqrt{\frac{2y_{0}}{g}}

En donde:

y_{0}: es la altura inicial = 50 m

g: es la gravedad = 10 m/s²

t = \sqrt{\frac{2y_{0}}{g}} = \sqrt{\frac{2*50 m}{10 m/s^{2}}} = 3.2 s

Entonces, el tiempo requerido para llegar al suelo es 3.2 s.

b) La rapidez de la pelota justo antes del choque es el siguiente:

v_{f} = v_{0} - gt

En donde:

v_{0}: es la velocidad inicial = 0 (dado que se deja caer en resposo)

v_{f} = v_{0} - gt = 0 - 10 m/s^{2}*3.2 s = -32 m/s

Por lo tanto, la rapidez de la pelota justo en el momento anterior del choque es -32 m/s (el signo negativo es porque la pelota está cayendo).

Espero que te sea de utilidad!

6 0
3 years ago
WILL GIVE BRAINLIEST
Vladimir [108]

Answer:

2\:\mathrm{m/s^2}

From Newton's 2nd Law, we have \Sigma F=ma. Substituting given values, we have:

40=20a,\\a=\frac{40}{20}=\boxed{2\:\mathrm{m/s^2}}

7 0
3 years ago
If I push on the wall with 75 Newtons of force, the wall will push back with ______
Sauron [17]

Answer:

(F)reaction = - 75 N

where, negative sign shows opposite direction.

Explanation:

This question can be answered using Newton's third law of motion. The Newton's Third Law of Motion states that for every action force there is an equal but opposite reaction force.

(F)action = - (F)reaction

Hence, in our scenario if we consider the 75 Newton force applied on the wall to be the action force then the reaction force of the wall must be equal to it in opposite direction. Therefore, the reaction push of the wall must be equal to 75 N.

<u>(F)reaction = - 75 N</u>

<u>where, negative sign shows opposite direction.</u>

6 0
3 years ago
To stop a car, first you require a certain reaction time to begin braking; then the car slows under the constant braking deceler
kirza4 [7]

Answer:

a.) 2.66 seconds for 79.2 km/h and 1.82 seconds for 47.8 km/h

b.)-4.13 m/s2 for 79.2 km/h and -3.63 m/s2 for 47.8 km/h

Explanation:

Now for (a)

time = velocity/distance

for velocity = 79.2 km/h and distance 0.0586 km

t = (0.0586/79.2)*3600

t = 2.66 seconds (Please note that multiplication with 3600 is to convert hours into seconds)

for velocity 47.8 km/h and distance 0.0242 km

t = (0.0242/47.8)*3600

t = 1.82 seconds

Now for (b)

2as = vf2-vi2

so,

2a(58.6) = -(79.2*1000/3600)^2 (Please note that multiplication and division with 1000 and 3600 respectively is to convert speed unit from km/h to m/s)

a = -4.13 m/s2 for 58.6 m

and

2a(24.2) = -(47.8*1000/3600)^2

a = -3.63 m/s2 for 24.2 m.

Please note that "-" sign express the deceleration.

5 0
3 years ago
A sanding disk with rotational inertia 3.8 x 10-3 kg·m2 is attached to an electric drill whose motor delivers a torque of magnit
Elis [28]

Answer:

(a) Angular momentum of disk is 1.343\, \frac{kg.m^{2}}{s}

(b) Angular velocity of the disk is 353\frac{rad}{s}

Explanation:

Given

Rotational inertia of the disk , I=3.8\times 10^{-3}kg.m^{2}

Torque delivered by the motor , \tau =17N.m

Torque is applied for duration , \Delta t=79ms=0.079s

(a)

Magnitude of angular momentum of the disk = Angular impulse produced by the torque

\therefore L=\tau \Delta t=17\times 0.079\frac{kg.m^{2}}{s}

=>L=1.343\, \frac{kg.m^{2}}{s}

Thus angular momentum of disk is 1.343\, \frac{kg.m^{2}}{s}

(b)

Since Angular momentum , L=I\omega

where \omega= Angular velocity of the disk

=>\omega =\frac{L}{I}=\frac{1.343}{3.8\times 10^{-3}}\frac{rad}{s}

\therefore \omega =353\frac{rad}{s}

Thus angular velocity of the disk is 353\frac{rad}{s}

5 0
4 years ago
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