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exis [7]
3 years ago
8

Use the diagram to answer the question. What happens at night?

Physics
2 answers:
Svet_ta [14]3 years ago
8 0

Answer:

Land breeze occurs at night

Explanation:

Land breeze is usually defined as the wind that blows from the land areas to the ocean surface. It occurs during the night time. It is because the land areas have the ability to release heat at a faster rate, in comparison to the ocean water bodies. When the land areas cools, the wind carries the cold and denser prevailing air and reaches the ocean surface in order to balance the warm rising air from the oceans. This is how the heat on earth is being balanced by the simultaneous occurrence of land and sea breeze.

melamori03 [73]3 years ago
7 0
The return flow goes to the right and instead of sea breeze, there's land breeze.
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A doubly ionized molecule (i.e., a molecule lacking two electrons) moving in a magnetic field experiences a magnetic force of 5.
Kobotan [32]

Explanation:

The given data is as follows.

           F = 5.75 \times 10^{-16} N

          q = 1.6 \times 10^{-19} C

          v = 385 m/s

       sin (63.9^{o}) = 0.876

Now, we will calculate the magnitude of magnetic field as follows.

              B = \frac{F}{qv sin (\theta)}

                  = \frac{5.75 \times 10^{-16} N}{1.6 \times 10^{-19} C \times 385 m/s \times 0.876}

                  = 0.01065 \times 10^{3} T

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4 0
3 years ago
The ___ model of the atom states that an electron's exact location within an atom can not be determined, but its probable locati
Dima020 [189]
The _quamtum mechanical_ model of the atom states that an electron's exact location within an atom can not be determined, but its probable location can be estimated within a three-dimensional region called an atomic orbital and that an electron's properties within an orbital can only be described by a set of mathematical values called a quantum number.
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3 years ago
A bowler throws a bowling ball of radius R = 11 cm down the lane with initial speed v₀ = 7.5 m/s. The ball is thrown in such a w
salantis [7]

Answer:

a) t = 0.74s

b) D = 4.76m

c) Vf = 5.35m/s

Explanation:

The ball starts rolling when Vf = ωf*R.

We know that:

Vf = Vo - a*t

ωf = ωo + α*t

With a sum of forces on the ball:

Ff = m*a

\mu*N = m*a

\mu*m*g = m*a

a=\mu*g=2.9m/s^2

With a sum of torque on the ball:

Ff*R = I*\alpha

\mu*m*g*R = 2/5*m*R^2*\alpha

\alpha=5/2*\mu*g/R=65.9rad/s^2

Replacing both accelerations:

Vo - a*t=\alpha*t*R

7.5 - 2.9*t=65.9*t*0.11

t=0.74s

The distance will be:

D = Vo*t-1/2*a*t^2

D = 4.76m

Final velocity:

Vf=Vo-a*t

Vf=5.35m/s

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