Answer:
a) t = 3.2 s
b) 
Explanation:
a) El tiempo requerido para llegar al suelo se puede calcular usando la siguiente fórmula:

En donde:
: es la altura inicial = 50 m
g: es la gravedad = 10 m/s²

Entonces, el tiempo requerido para llegar al suelo es 3.2 s.
b) La rapidez de la pelota justo antes del choque es el siguiente:

En donde:
: es la velocidad inicial = 0 (dado que se deja caer en resposo)

Por lo tanto, la rapidez de la pelota justo en el momento anterior del choque es -32 m/s (el signo negativo es porque la pelota está cayendo).
Espero que te sea de utilidad!
Answer:

From Newton's 2nd Law, we have
. Substituting given values, we have:

Answer:
(F)reaction = - 75 N
where, negative sign shows opposite direction.
Explanation:
This question can be answered using Newton's third law of motion. The Newton's Third Law of Motion states that for every action force there is an equal but opposite reaction force.
(F)action = - (F)reaction
Hence, in our scenario if we consider the 75 Newton force applied on the wall to be the action force then the reaction force of the wall must be equal to it in opposite direction. Therefore, the reaction push of the wall must be equal to 75 N.
<u>(F)reaction = - 75 N</u>
<u>where, negative sign shows opposite direction.</u>
Answer:
a.) 2.66 seconds for 79.2 km/h and 1.82 seconds for 47.8 km/h
b.)-4.13 m/s2 for 79.2 km/h and -3.63 m/s2 for 47.8 km/h
Explanation:
Now for (a)
time = velocity/distance
for velocity = 79.2 km/h and distance 0.0586 km
t = (0.0586/79.2)*3600
t = 2.66 seconds (Please note that multiplication with 3600 is to convert hours into seconds)
for velocity 47.8 km/h and distance 0.0242 km
t = (0.0242/47.8)*3600
t = 1.82 seconds
Now for (b)
2as = vf2-vi2
so,
2a(58.6) = -(79.2*1000/3600)^2 (Please note that multiplication and division with 1000 and 3600 respectively is to convert speed unit from km/h to m/s)
a = -4.13 m/s2 for 58.6 m
and
2a(24.2) = -(47.8*1000/3600)^2
a = -3.63 m/s2 for 24.2 m.
Please note that "-" sign express the deceleration.
Answer:
(a) Angular momentum of disk is 
(b) Angular velocity of the disk is 
Explanation:
Given
Rotational inertia of the disk , 
Torque delivered by the motor , 
Torque is applied for duration , 
(a)
Magnitude of angular momentum of the disk = Angular impulse produced by the torque

=>
Thus angular momentum of disk is 
(b)
Since Angular momentum , 
where
= Angular velocity of the disk


Thus angular velocity of the disk is 