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3 years ago

If a 10-volt battery is placed across a 2-ohm resistance (R = 20), a current of

Physics

1 answer:

attashe74 [19]3 years ago

4 0

Answer: current I = 0.5 A

Explanation:

Given that the

Potential difference V = 10V

Resistance R = 20 ohms

According to ohms law

V = IR

Where

V = potential difference

I = current

R = resistance

Make I the subject of formula

I = V/R

I = 10/20

I = 0.5 Ampere

More in details:

Our senses allow us to experience the world we live in, and are one of the key components of consciousness. ... This is why the study of our senses, or sensation, is considered to be such an important area of psychology, because it is one of the key components that makes consciousness possible.

7 0

3 years ago

A block slides down a slope inclined at 37 degrees. If the slope is frictionless and the block starts off at rest, how fast is i

lianna [129]

Answer:

Vf= 3.435 m/s

Explanation:

Given:

Initial velocity Vi =0 m/s (starting from Rest position)

θ = 37⁰

Distance S = 1 m

To find: Final Velocity Vf=?

fist we have to find the down slope net acceleration a = g sin θ

a= 9.81 sin 37⁰ = 5.9 m/s²

By 3rd equation of motion

2 a S= Vf² - Vi²

Vf = Square root ( 2 × 5.9 m/s² × 1 + 0 m/s)

Vf = Square root (11.8)

Vf= 3.435 m/s

3 0

3 years ago

A rock is thrown directly upward from the edge of a flat roof of a building that is 56.3 meters tall. The rock misses the buildi

Vlada [557]

Explanation:

Given that,

Distance, d = -56.3 m

It strikes the ground 4.00 seconds after being thrown.

Using second equation of motion to find the speed was the rock thrown. So,

$d=ut+\dfrac{1}{2}at^2$

Here, a = -g

$d=ut-\dfrac{1}{2}gt^2\\\\-56.3=u(4)-4.9(4)^2\\\\-56.3=4u-78.4\\\\u=5.52\ m/s$

Let it will cover a distance of s meters. So,

$s=\dfrac{v^2-u^2}{-2g}\\\\s=\dfrac{0^2-(5.52)^2}{-2\times 9.8}\\\\s=1.55\ m$

4 0

3 years ago

Please answer my quastions

Neko [114]

Answer:

a) 120 N

b) 5 N

c) 0.2 N

d) Mass remains the same, and weight decreases.

Explanation:

Use the formula W = mg, where mass is in kg, and gravitational field strength in N/kg.

W = mg

= 12 × 10

= 120 N

500 g = 0.5 kg

W = mg

= 0.5 × 10

= 5 N

20 g = 0.02 kg

W = mg

= 0.02 × 10

= 0.2 N

Mass remains the same, and weight decreases.

6 0

3 years ago