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NISA [10]
3 years ago
6

What are the three states of matter?

Chemistry
1 answer:
nataly862011 [7]3 years ago
4 0

SOLID

LIQUID

GASES .......

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5. A sample of pure acetyl salicylic acid had a mass of 0.268 grams. It was dissolved in NaOH and diluted to 500.00mL in a volum
Elza [17]

Answer:

a. 5.36x10⁻⁴ g/mL

b. 4.29x10⁻⁵ g/mL

Explanation:

As the units for concentration are not specified, I'll respond using g/mL.

a. We <em>divide the sample mass by the final volume</em> in order to <u>calculate the concentration</u>:

  • 0.268 g / 500 mL = 5.36x10⁻⁴ g/mL

b. We can use C₁V₁=C₂V₂ for this question:

  • 8.00 mL * 5.36x10⁻⁴ g/mL = C₂ * 100.00 mL
  • C₂ = 4.29x10⁻⁵ g/mL
4 0
3 years ago
What are easy ways to<br>Study Chemistry ??​
Elina [12.6K]

Answer:

seneca

past papers

take notes from videos

Explanation:

very good website, asks questions about the subject correct for your exam board and gives correct answers and explanations

exam papers always help

7 0
2 years ago
What is the Molar Mass
Natasha2012 [34]
The molar mass<span> is the </span>mass<span> of a  chemical element or a chemical compound (g) divided by the amount of substance (mol).

Hope this helps!</span>
5 0
3 years ago
Read 2 more answers
What process takes place before an article is published in a scientific journal/
Goshia [24]
Before an article is published in a scientific journal or in any "peer-reviewed" journal the article is reviewed thoroughly by scholars from the journal as well as peers or scholars of the articles author from the same field. This process occurs to provide credibility to the ideas being published and so that readers and other scholars can rely on the validity of the material being published. 
7 0
3 years ago
Given the balanced equation, 2 H2 + O2 -&gt; 2 H2O, answer the following
9966 [12]

Answer: O_2 is the limiting reagent

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} H_2=\frac{10.0g}{2g/mol}=5.00moles

\text{Moles of} O_2=\frac{20.0g}{32g/mol}=0.625moles

The balanced chemical reaction is :

2H_2+O_2\rightarrow 2H_2O

According to stoichiometry :

1 moles of O_2 require = 2 moles of H_2

Thus 0.625 moles of O_2 will require=\frac{2}{1}\times 0.625=1.25moles of H_2

Thus O_2 is the limiting reagent as it limits the formation of product and H_2 is the excess reagent as it is present more than the required amount.

8 0
3 years ago
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